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muminat
2 years ago
8

A student is trying to develop a model of an instant heat pack. What is the essential characteristic of the chemical reaction th

at the student should
use to develop the heat pack?
O A The standard enthalpy of reaction should be zero.
о В.
The standard enthalpy of reaction should be negative.
OC. The enthalpy of formation of reactants should be positive.
D. The enthalpy of formation of products should be negative.
Chemistry
1 answer:
Lana71 [14]2 years ago
3 0

The standard enthalpy of reaction should be negative.

<h3>What is enthalpy?</h3>

A thermodynamic quantity equivalent to the total heat content of a system. It is equal to the internal energy of the system plus the product of pressure and volume.

Inside the heat pack are two chemicals that get mixed when you smush them together. As they mix, some weak bonds are broken, which takes a little bit of energy. But new, stronger bonds form which release energy. Releasing that energy causes the surroundings to heat up.

Hence, option B is correct.

Learn more about enthalpy here:

brainly.com/question/13775366

#SPJ1

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It reduces the need to import goods

Explanation:

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Why can you never see the far side of the mood from earth?
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4 0
3 years ago
Calculate the pH of adding 20 mL of 1 M NaOH solution to 100 mL of a 1 M acetic acid (CH3COOH) solution and 880 mL of distilled
Dafna1 [17]

<u>Answer:</u> The pH of the solution is 4.14

<u>Explanation:</u>

To calculate the number of moles for given molarity, we use the equation:

\text{Molarity of the solution}=\frac{\text{Moles of solute}\times 1000}{\text{Volume of solution (in mL)}}

  • <u>For NaOH:</u>

Molarity of NaOH = 1 M

Volume of solution = 20 mL

Putting values in above equation, we get:

1M=\frac{\text{Moles of NaOH}\times 1000}{20mL}\\\\\text{Moles of NaOH}=\frac{1\times 20}{1000}=0.02mol

  • <u>For acetic acid:</u>

Molarity of acetic acid solution = 0.26 M

Volume of solution = 100 mL

Putting values in above equation, we get:

1M=\frac{\text{Moles of acetic acid}\times 1000}{100mL}\\\\\text{Moles of acetic acid}=\frac{1\times 100}{1000}=0.1mol

The chemical reaction for NaOH and acetic acid follows the equation:

                   CH_3COOH+NaOH\rightarrow CH_3COONa+H_2O

<u>Initial:</u>           0.100            0.020

<u>Final:</u>            0.080               -              0.020            

Volume of solution = 20 + 100 = 120 mL = 0.120 L    (Conversion factor:  1 L = 1000 mL)

To calculate the pH of acidic buffer, we use the equation given by Henderson Hasselbalch:

pH=pK_a+\log(\frac{[salt]}{[acid]})

pH=pK_a+\log(\frac{[CH_3COONa]}{[CH_3COOH]})

We are given:

pK_a = negative logarithm of acid dissociation constant of acetic acid = 4.74

[CH_3COONa]=\frac{0.020}{0.120}

[CH_3COOH]=\frac{0.080}{0.120}

pH = ?

Putting values in above equation, we get:

pH=4.74+\log(\frac{0.020/0.120}{0.080/0.120})\\\\pH=4.14

Hence, the pH of the solution is 4.14

5 0
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vodka [1.7K]

Answer:

Acid solutions have pH values lesser than

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it turn blue litmus paper red

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