Below is the structure of Benzilic Acid and IR spectrum. First common thumb rule for elucidating IR spectrum is to find a broad and intense signal between 1690-1800 cm⁻¹, If present! Then its for Carbonyl group. Secondly, watch for broad peak around 3400-3600 cm⁻¹, peak at this frequency is given by the -OH (Hydroxyl) group of Alcohols, andthe broadness is due to Association effect (Hydrogen bonding). Third, aif a wide band between 2500-3300 cm⁻¹ is present it shown -OH of carboxylic acid.
Result: Carbony Group = 1640 cm⁻¹
Carboxyl -OH Group = 2950 cm⁻¹
Alcohol -OH = 3400 cm⁻¹
Answer:
- <u>C₂H₄</u> (option number 4)
Explanation:
A hydrocarbon with a <em>double bond</em> in its carbon skeleton is an alkene and has the general form:
-
.
This is, the number of hydrogen atoms is twice the number of carbon atoms.
On the other hand, alkanes have only single bonds, and the compounds with a triple bond in its carbon skeleton are alkynes.
Review each choice:
1) <u>C₃H₈:</u>
- In this case, the number of hydrogen atoms is 2×3 + 2 = 6 + 2 = 8, which is corresponds to an alkane, not an alkene.
2)<u> C₂H₆</u>
- For this, the number of hydrogen atoms is 2 × 2 + 2 = 4 + 2 = 6. Again an alkane, not alkene.
3) <u>CH₄</u>
- Hydrogen atoms: 1 × 2 + 2 = 4 ⇒ an alkane
4) <u>C₂H₄ </u>
- Hydrogen atoms: 2 × 2 = 4. This is precisely the relation for an alkene, so this is the hydrocarbon that has a double bond in its carbon skeleton.
- The chemical formula may be writen as CH₂ = CH₂, to show the double bond.
So, this is the correct answer.
5) <u>C₂H₂</u>
- Hydrogen atoms: 2 × 2 - 2 = 4 - 2 = 2. This relation of carbon and hydrogen atoms corresponds to a compound with triple bond, i.e an alkyne: CH≡CH.
Carbon has the ability to form multiple bonds because it has four valence electrons. Having four valence electrons means that carbon has a lot of space to form bonds with other atoms, or multiple bonds, in order to reach the full octet.
Hope this helps!! :)
[Co(CN)₆]³⁻ → Yellow
[Co(NH₃)₆]³⁺ → Orange
[CoF₆]³⁻ → Blue
Explanation:
- All the given compounds have octahedral geometry but the ligand in each are different with the same metal ion.
- Ligands strength order: CN⁻ > NH₃ > F⁻
- The ligand CN will act as a strong field ligand so that the splitting is maximum when compared to NH₃ and F⁻
- If the splitting is more, the energy required for transition is more, and the wavelength is inversely proportional to energy.
- So CN complex will absorb at lower wavelength (yellow color)
