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Alekssandra [29.7K]
2 years ago
6

Lucia is playing with magnetic toy vehicles. She has two identical toy vehicles (purple and pink) that start on opposite sides o

f a center magnet that cannot move. She moves both vehicles one space closer to the center magnet.
How did the potential energy of the two vehicles change? Did the potential energy of one vehicle change more than the other? Why do you think so?

Chemistry
2 answers:
NemiM [27]2 years ago
8 0

Answer:

The potential energy of the two vehicles increased because they were moved against the magnatic forces. The potential energy of the pink car increased more then the potential energy of the purple car because the pink car was closer to the center magnet.

Explanation: I had this same exact question on a quiz and this was my response and I got a 100%

pentagon [3]2 years ago
3 0

Answer:

The potential energy of both toy vehicles (purple and pink) decreased. Since the pink toy was moved closer to the magnet, it will have less potential energy because of the short distance it will take to travel to the magnet. Although the purple toy is now closer to the magnet, it is still pretty far and will have a somewhat big potential energy when traveling to the magnet.

Explanation:

Hey, I'm in middle school and I had the same question for a science test, I'm not sure if I am correct but this is what I have.

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Holly has an unknown substance in a beaker. she wants to determine the relative ph of the unknown substance. she places a piece
AURORKA [14]

Blue litmus paper turns red in the presence of an acid. Therefore, it can be assumed that the substance in the beaker is an acid.

Acids have a pH level of less than 7. Consequently, it can be assumed that the substance has a pH level less than 7.

6 0
3 years ago
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What mass of copper is consumed in the reaction with hydrochloric acid if 10.0 g of gas is collected?
brilliants [131]

Answer:

317 g

Explanation:

Cu + 2HCl --> CuCl2 +H2

1      :     2           1 : 1

1 mole of Cu  = 63.5 g

1 mole of  H2 = 2g

1 mole  Cu produces = 1 mole of H2

63.5 g of Cu produces = 2 g of H2

So

10 g of H2 will be produced from =  (63.5/2)*10 = 317 g of Copper

4 0
2 years ago
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Zinaida [17]
Number 13 is D. Mendeleev. He was a Russian chemist and inventor who formulated the periodic table.
5 0
2 years ago
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If you combine 230.0 mL 230.0 mL of water at 25.00 ∘ C 25.00 ∘C and 120.0 mL 120.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is t
Thepotemich [5.8K]

<u>Answer:</u> The final temperature of the mixture is  49°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}

  • <u>For cold water:</u>

Density of cold water = 1 g/mL

Volume of cold water = 230.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{230.0mL}\\\\\text{Mass of water}=(1g/mL\times 230.0mL)=230g

  • <u>For hot water:</u>

Density of hot water = 1 g/mL

Volume of hot water = 120.0 mL

Putting values in above equation, we get:

1g/mL=\frac{\text{Mass of water}}{120.0mL}\\\\\text{Mass of water}=(1g/mL\times 120.0mL)=120g

When hot water is mixed with cold water, the amount of heat released by hot water will be equal to the amount of heat absorbed by cold water.

Heat_{\text{absorbed}}=Heat_{\text{released}}

The equation used to calculate heat released or absorbed follows:

Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})

m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]      ......(1)

where,

q = heat absorbed or released

m_1 = mass of hot water = 120 g

m_2 = mass of cold water = 230 g

T_{final} = final temperature = ?°C

T_1 = initial temperature of hot water = 95°C

T_2 = initial temperature of cold water = 25°C

c = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

120\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]

T_{final}=49^oC

Hence, the final temperature of the mixture is  49°C

4 0
3 years ago
An aerosol can with a temperature of 292 K and a pressure of 1.25 atm was left outside in the sun on a hot summer day. The press
garik1379 [7]

Answer:

310.69K

Explanation:

Given parameters:

Initial temperature T₁ = 292K

Initial pressure P₁ = 1.25atm

Final pressure P₂ = 1.33atm

Unknown:

Final temperature T₂ = ?

Solution

To find the unkown, we need to apply the combined gas law. From the combined gas law, it can be deduced that at constant volume, the pressure of a give mass or mole of gas varies directly with the absolute temperature.

Since the same aerosol can is heated, the volume is constant.

          \frac{P_{1} }{T_{1} } =  \frac{P_{2} }{T_{2} }

Now, we have to make T₂ the subject of the formula:

      T₂ =  \frac{P_{2}  x T_{1}  }{P_{1} }

       T₂ =  \frac{1.33  x 292  }{1.25 } =  310.69K

6 0
2 years ago
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