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3 years ago

8

Match the given equation with the verbal description of the surface: A. Circular Cylinder B. Plane C. Cone D. Half plane E. Sphe

re F. Elliptic or Circular Paraboloid

1 answer:

sdas [7]3 years ago

8 0

Answer:

A. Circular Cylinder

r=4

$\sqrt{x^{2}+y^{2} }$ =4 independent from z

B. Plane

ρ cos φ ( )=4

spherical coordinates

z=4

C. Cone

φ = π/3

φ spherical coordinates

D. Half Plane

θ = π/3

Cylindrical Coordinates, do not have portion in 3rd quadrant that why its only half a plane.

E. Sphere:

ρ =2cos φ ( )

Spherical Coordinates

ρ =2×z/ρ

$p^{2}$ =2z

$x^{2} +y^{2} +z^{2}$ = $p^{2}$

$x^{2} +y^{2}+z-1^{2}$ =1

F. Elliptic or Circular Parabola

z= $r^{2}$

z= $r^{2}$ = $x^{2} +y^{2}$

z= $y^{2}$

note: pics are attached

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4 years ago

Based on Newton's law of motion, which combination of rocket bodies and engine will result in the acceleration of 40 m/s ^2 at t

ad-work [718]

The question is incomplete. The complete question is :

The Rocket Club is planning to launch a pair of model rockets. To build the rocket, the club needs a rocket body paired with an engine. The table lists the mass of three possible rocket bodies and the force generated by three possible engines.

A 4-column table with 3 rows. The first column labeled Body has entries 1, 2, 3. The second column labeled Mass (grams) has entries 500, 1500, 750. The third column labeled Engine has entries 1, 2, 3. The fourth column labeled Force (Newtons) has entries 25, 20, 30.

Based on Newton’s laws of motion, which combination of rocket bodies and engines will result in the acceleration of 40 m/s2 at the start of the launch?

Body 3 + Engine 1

Body 2 + Engine 2

Body 1 + Engine 2

Body 1 + Engine 1

Solution :

Given :

Body Mass (gram) Engine Force (newtons)

1 500 1 25

2 1500 2 20

3 750 3 30

The body 1 has a mass of 500 gram which is equal to 0.5 kg

And engine 2 has a force of 20 newtons.

We know that according to Newton's laws of motion,

Force = mass x acceleration

20 = 0.5 x acceleration

Acceleration $=\frac{20}{0.5}$

$=\frac{200}{5}$

$= 40 \ m/s^2$

Therefore, based on laws of motion of Newton, the Body 1 + Engine 2 combination of the rocket bodies and engines will result in an acceleration of $40 \ m/s^2$ at the start of the launch.

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3 years ago

OLga [1]

Answer:

Doppler Theory

Explanation:

it's a theory regarding the change in wave frequency during the relative motion between a wave source and its observer.

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2 years ago

The electron gun in a television tube accelerates electrons (mass = 9.11x10^-31 kg, charge = 1.6 x 10^-19C) from rest to 3 x10^7

stich3 [128]

Answer:

Electric field acting on the electron is 127500 N/C.

Explanation:

It is given that,

Mass of an electron, $m=9.11\times 10^{-31}\ kg$

Charge on electron, $q=1.6\times 10^{-19}\ C$

Initial speed of electron, u = 0

Final speed of electron, $v=3\times 10^7\ m/s$

Distance covered, s = 2 cm = 0.02 m

We need to find the electric field required. Firstly, we will find the acceleration of the electron from third equation of motion as :

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{(3\times 10^7)^2-0}{2\times 0.02}$

$a=2.25\times 10^{16}\ m/s^2$

According to Newton's law, force acting on the electron is given by :

F = ma

$F=9.1\times 10^{-31}\times 2.25\times 10^{16}$

$F=2.04\times 10^{-14}\ N$

Electric force is given by :

F = q E, E = electric field

$E=\dfrac{F}{q}$

$E=\dfrac{2.04\times 10^{-14}}{1.6\times 10^{-19}}$

E = 127500 N/C

So, the electric field is 127500 N/C. Hence, this is the required solution.

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3 years ago

What is the frequency of a sound wave with a wavelength of 0.04 meter in air? What type of wave is

Viktor [21]

8500 Hz and Longitudinal

Speed = frequency x wavelength

Speed of sound at 20 degrees Celsius is approximately 340 m/s

4 0

3 years ago

Read 2 more answers