<span>a. A solid will gain kinetic energy and become a liquid.</span>
Answer:
![\mathbf{\beta = 123.75 \ dB}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cbeta%20%3D%20123.75%20%5C%20dB%7D)
Explanation:
From the question, using the expression:
![125 \ dB = 10 \ log (\dfrac{I}{I_o})](https://tex.z-dn.net/?f=125%20%5C%20dB%20%3D%2010%20%5C%20log%20%28%5Cdfrac%7BI%7D%7BI_o%7D%29)
where;
![I_o = 10^{-12} \ W/m^2](https://tex.z-dn.net/?f=I_o%20%3D%2010%5E%7B-12%7D%20%5C%20W%2Fm%5E2)
![I = 10^{12.5} \times 10^{-12} \ W/m^2](https://tex.z-dn.net/?f=I%20%3D%2010%5E%7B12.5%7D%20%5Ctimes%2010%5E%7B-12%7D%20%5C%20W%2Fm%5E2)
![I = 3.162 \ W/m^2](https://tex.z-dn.net/?f=I%20%3D%203.162%20%5C%20W%2Fm%5E2)
This is a combined intensity of 4 speakers.
Thus, the intensity of 3 speakers = ![\dfrac{3.162\times 3}{4}](https://tex.z-dn.net/?f=%5Cdfrac%7B3.162%5Ctimes%203%7D%7B4%7D)
= 2.372 W/m²
Thus;
![\beta = 10 \ log ( \dfrac{2.372}{10^{-12}} ) \ W/m^2](https://tex.z-dn.net/?f=%5Cbeta%20%3D%2010%20%5C%20%20log%20%28%20%5Cdfrac%7B2.372%7D%7B10%5E%7B-12%7D%7D%20%29%20%5C%20W%2Fm%5E2)
![\mathbf{\beta = 123.75 \ dB}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cbeta%20%3D%20123.75%20%5C%20dB%7D)
Answer:
frying an egg is conduction because the pan is touching the stove and the pan is touching the eggs
Explanation:
The work done on the box by the applied force is zero.
The work done by the force of gravity is 75.95 J
The work done on the box by the normal force is 75.95 J.
<h3>The given parameters:</h3>
- Mass of the box, m = 3.1 kg
- Distance moved by the box, d = 2.5 m
- Coefficient of friction, = 0.35
- Inclination of the force, θ = 30⁰
<h3>What is work - done?</h3>
- Work is said to be done when the applied force moves an object to a certain distance
The work done on the box by the applied force is calculated as;
![W = Fd cos(\theta)\\\\W = (ma)d \times cos(\theta)](https://tex.z-dn.net/?f=W%20%3D%20Fd%20cos%28%5Ctheta%29%5C%5C%5C%5CW%20%3D%20%28ma%29d%20%5Ctimes%20cos%28%5Ctheta%29)
where;
a is the acceleration of the box
The acceleration of the box is zero since the box moved at a constant speed.
![W = (0) d \times cos(30)\\\\W = 0 \ J](https://tex.z-dn.net/?f=W%20%3D%20%280%29%20d%20%5Ctimes%20cos%2830%29%5C%5C%5C%5CW%20%3D%200%20%5C%20J)
The work done by the force of gravity is calculated as follows;
![W = mg \times d\\\\W = 3.1 \times 9.8 \times 2.5 \\\\W = 75.95 \ J](https://tex.z-dn.net/?f=W%20%3D%20mg%20%5Ctimes%20d%5C%5C%5C%5CW%20%3D%203.1%20%5Ctimes%209.8%20%5Ctimes%202.5%20%5C%5C%5C%5CW%20%3D%2075.95%20%5C%20J)
The work done on the box by the normal force is calculated as follows;
![W = (F_n) \times d\\\\W = (mg + F sin\theta) \times d\\\\W = (mg + 0) \times d\\\\W = mgd\\\\W = 3.1 \times 9.8 \times 2.5\\\\W = 75.95 \ J](https://tex.z-dn.net/?f=W%20%3D%20%28F_n%29%20%5Ctimes%20d%5C%5C%5C%5CW%20%3D%20%28mg%20%2B%20F%20sin%5Ctheta%29%20%5Ctimes%20d%5C%5C%5C%5CW%20%3D%20%28mg%20%2B%200%29%20%5Ctimes%20d%5C%5C%5C%5CW%20%3D%20mgd%5C%5C%5C%5CW%20%3D%203.1%20%5Ctimes%209.8%20%5Ctimes%202.5%5C%5C%5C%5CW%20%3D%2075.95%20%5C%20J)
Learn more about work done here: brainly.com/question/8119756
I believe it would be a musical note