Answer:
c) Both the parts will weigh the same
Explanation:
center of gravity is based on weight so if you cut down the center of gravity you would have 2 equal parts
(might be D if it is cutting against the center of gravity)
Answer:
b) d = 0.71 Km
Explanation:
Car kinematics
Car 1 moves with uniformly accelerated movement
Formula (1)
d: displacement in meters (m)
v₀: initial speed in m/s
vf: final speed in m/s
a: acceleration in m/s²
Equivalences:
1mile = 1609.34 meters
1 hour = 3600s
1km = 1000m
Known data


a = -0.5 m/s²
Distance calculation
We replace data in the Formula (1)




Answer:
K.E = 100 J
Final P.E = 100 J
Explanation:
The kinetic energy of any object can be given by the following formula:

where,
K.E = Kinetic Energy
m = mass of ball = 2 kg
v = speed of ball
Initially, v = 10 m/s. Therefore, the initial K.E is given as:

<u>K.E = 100 J</u>
Now, at the highest point the K.E of the ball becomes zero. because the ball stops for a moment at the highest point and its velocity becomes zero. So, from Law of Conservation of energy:
Initial K.E + Initial P.E = Final K.E + Final P.E
Initial P.E is also zero due to zero height initially.
K.E + 0 = 0 + Final P.E
<u>Final P.E = 100 J</u>
<span>The flight controls must be held with left aileron up and elevator neutral while taxiing a tricycle-gear equipped airplane with a left quartering tailwind. In aircraft, ailerons are placed on the trailing edge of each wing near the wingtips and can be moved up and down. So when the left aileron is up, the movement of the airplane moves to the left and turns the wheel in a counterclockwise direction while at the same time, the right aileron is down.
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Actual displacement that he required to move
towards North
Displacement that he moved due to snow is
at 47 degree North of East
now in vector component form we can say



now the displacement that is more required to reach the destination is given as



so the magnitude of the displacement is given as


its direction is given as

so it is 5.54 km towards 5.38 degree North of West.