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vladimir2022 [97]
3 years ago
6

Why centre of gravity of ring is out of its body

Physics
1 answer:
earnstyle [38]3 years ago
8 0
There's no reason why the center of gravity must be in a place where
there is a any mass. 

The center of gravity is simply a LOCATION ... the place where the 
amount of mass in any direction from it is the same amount. 

For that matter, whenever you know the location of the center of gravity
for ANY object, you can always go in there and scoop our a tiny spherical
hole at that place.  Then the center of gravity won't move, but it will be in an
empty space, 'outside the body' of the object.

Here are a few more points to ponder:

-- The center of gravity of a basketball, beach ball, tennis ball, or any other
inflated ball is the center of the ball, where there is no part of the skin.

-- The center of gravity of a party balloon is somewhere inside the balloon,
where there is no rubber.  If the balloon is spherical, then its center of gravity
is the center of the sphere.

-- The center of gravity of a square is the center of the square, not on any
of its sides.

-- The center of gravity of a triangle is the centroid of the triangle, not on any
of its sides.

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larisa [96]

Answer:

12.6332454263 m/s

Explanation:

m = Mass of car

v = Velocity of the car

\mu = Coefficient of static friction = 0.638

g = Acceleration due to gravity = 9.81 m/s²

r = Radius of turn = 25.5 m

When the car is on the verge of sliding we have the force equation

\dfrac{mv^2}{r}=\mu mg\\\Rightarrow v=\sqrt{\mu gr}\\\Rightarrow v=\sqrt{0.638\times 9.81\times 25.5}\\\Rightarrow v=12.6332454263\ m/s

The speed of the car that will put it on the verge of sliding is 12.6332454263 m/s

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3 years ago
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Answer:

The answer

Explanation:

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1. The statement about Newton's reflecting telescope contains 1 error. Find the error, write it, and
Jlenok [28]

Answer:

i. The error is the rough convex mirror.

ii. This should be replaced with a smooth convex morror.

Explanation:

Reflection is dependent on the surface involved and has two types; diffuse and specular. When the surface is rough, diffused reflection is observed. The surface causes a distortion of the incident light (the rays would be reflected at different angles to one another) after reflection. This makes some rays to interfere with one another. While specular reflection is observed with a smooth surface.

In the statement, the rough convex mirror would produce a distorted reflection which would produce diffused reflection. The effect is that few or no rays (depending on the degree of how rough the surfce is) would be reflected to the other smooth, flat diagonal mirror.

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Arada [10]

Answer:

I think it c

Explanation:

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