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vladimir2022 [97]
2 years ago
6

Why centre of gravity of ring is out of its body

Physics
1 answer:
earnstyle [38]2 years ago
8 0
There's no reason why the center of gravity must be in a place where
there is a any mass. 

The center of gravity is simply a LOCATION ... the place where the 
amount of mass in any direction from it is the same amount. 

For that matter, whenever you know the location of the center of gravity
for ANY object, you can always go in there and scoop our a tiny spherical
hole at that place.  Then the center of gravity won't move, but it will be in an
empty space, 'outside the body' of the object.

Here are a few more points to ponder:

-- The center of gravity of a basketball, beach ball, tennis ball, or any other
inflated ball is the center of the ball, where there is no part of the skin.

-- The center of gravity of a party balloon is somewhere inside the balloon,
where there is no rubber.  If the balloon is spherical, then its center of gravity
is the center of the sphere.

-- The center of gravity of a square is the center of the square, not on any
of its sides.

-- The center of gravity of a triangle is the centroid of the triangle, not on any
of its sides.

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If I push on the wall with 75 Newtons of force, the wall will push back with __
Scilla [17]

Answer: 0

Explanation:

75 newtons will push back canceling it out make it 0

7 0
3 years ago
The velocity of a 48.0 g shell leaving a 2.95 kg rifle is 391. m/s. What is the recoil velocity of the rifle?
Monica [59]

Hi there!

\large\boxed{  -6.36m/s}

Use the equation:

v_{2} = -\frac{m_{1}}{m_{2}} v_{1}

Where m2 and v2 deal with the larger object, and m1 and v1 with the smaller object. Plug in the given values:

v2 = ?

m1 = 0.048 kg (converted)

m2 = 2.95

v1 = 391

v_{2} = -\frac{0.048}{2.95} *391

v_{2} = -6.36m/s

8 0
3 years ago
How could the action force of a canoe moving through water be increased?.
BaLLatris [955]
There are several actions that can be used to increase the action force of a canoe that is moving through water. One can increase the rate of striking or strike harder than before with a bigger paddle. Using a lighter canoe can also be helpful for increasing the speed. I hope the answer comes to your help.
4 0
3 years ago
Which process best describes part of a scientific investigation?
lara31 [8.8K]

the answer is c because it is the 3rd step in the scientific analysis steps

5 0
3 years ago
Read 2 more answers
A Neglecting air resistance, a ball projected straight upward so it remains in the air for 10 seconds needs an initial speed of
ololo11 [35]

Answer:

The initial velocity is 50 m/s.

(C) is correct option.

Explanation:

Given that,

Time = 10 sec

For first half,

We need to calculate the height

Using equation of motion

v^2=u^2+2gh

h =\dfrac{v^2}{2g}....(I)

For second half,

We need to calculate the time

Using equation of motion

h =ut+\dfrac{1}{2}gt_{2}^2

h=0+\dfrac{1}{2}gt_{2}^2

t_{2}=\sqrt{\dfrac{2h}{g}}

Put the value of h from equation (I)

t_{2}=\sqrt{\dfrac{2\times v^2}{g^2}}

t_{2}=\dfrac{v}{g}

According to question,

t_{1}+t_{2}=10

t_{1}=t_{2}

Put the value of t₁ and t₂

\dfrac{v}{g}+\dfrac{v}{g}=10

\dfrac{2v}{g}=10

v=\dfrac{10\times g}{2}

Here, g = 10

The initial velocity is

v=\dfrac{10\times10}{2}

v=50\ m/s

Hence, The initial velocity is 50 m/s.

3 0
2 years ago
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