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vladimir2022 [97]
3 years ago
6

Why centre of gravity of ring is out of its body

Physics
1 answer:
earnstyle [38]3 years ago
8 0
There's no reason why the center of gravity must be in a place where
there is a any mass. 

The center of gravity is simply a LOCATION ... the place where the 
amount of mass in any direction from it is the same amount. 

For that matter, whenever you know the location of the center of gravity
for ANY object, you can always go in there and scoop our a tiny spherical
hole at that place.  Then the center of gravity won't move, but it will be in an
empty space, 'outside the body' of the object.

Here are a few more points to ponder:

-- The center of gravity of a basketball, beach ball, tennis ball, or any other
inflated ball is the center of the ball, where there is no part of the skin.

-- The center of gravity of a party balloon is somewhere inside the balloon,
where there is no rubber.  If the balloon is spherical, then its center of gravity
is the center of the sphere.

-- The center of gravity of a square is the center of the square, not on any
of its sides.

-- The center of gravity of a triangle is the centroid of the triangle, not on any
of its sides.

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C. Hypothesis
The hypothesis is presented as an explanation of the observed results.
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3 years ago
At time t=0 a 2150 kg rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. This forc
amm1812

Explanation:

Given that,

Mass of the rocket, m = 2150 kg

At time t=0 a rocket in outer space fires an engine that exerts an increasing force on it in the +x−direction. The force is given by equation :

F=At^2

Here F = 888.93 N when t = 1.25 s

(c) We can find the value of A first as :

F=At^2\\\\A=\dfrac{F}{t^2}\\\\A=\dfrac{888.93}{(1.25)^2}\\\\A=568.91\ N/s^2

The value of A is 568.91\ N/s^2.

(a) Let J is the impulse does the engine exert on the rocket during the 4.0 s interval starting 2.00 s after the engine is fired. It is given in terms of force as :

J=\int\limits {F{\cdot} dt}

Limits will be from 2 s to 2+ 4 = 6 s

It implies :

J=\int\limits^6_2 {At^2{\cdot} dt}\\\\J=A\int\limits^6_2 {t^2{\cdot} dt}\\\\J=A\dfrac{t^3}{3}|_2^6\\\\J=568.91\times \dfrac{1}{3}\times (6^3-2^3)\\\\J=39444.42\ Ns

(b) Impulse is also equal to the change in momentum as :

J=m\Delta v\\\\\Delta v=\dfrac{J}{m}\\\\\Delta v=\dfrac{39444.42}{2150}\\\\\Delta v=18.34\ m/s

Hence, this is the required solution.

5 0
3 years ago
7. What is a chemical bond? A. The force that holds together the elements in a compound B. A representation of chemical properti
muminat
The answer to your question is A, The force that holds together elements in a compound.
6 0
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When a particle of charge q moves with a velocity v⃗ in a magnetic field B⃗ , the particle is acted upon by a force F⃗ exerted b
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Answer:

3.8\cdot 10^{-16}N

Explanation:

For a charged particle moving perpendicularly to a magnetic field, the magnitude of the force exerted on the particle is:

F=qvB

where

q is the magnitude of the charge of the particle

v is the velocity of the particle

B is the magnetic field strength

In this problem, we have

q=e=1.6\cdot 10^{-19} is the charge of the electron

v=6.0\cdot 10^6 m/s is the velocity

B=4.0\cdot 10^{-4}T is the magnetic field

Substituting into the formula, we find the force:

F=(1.6\cdot 10^{-19} C)(6.0\cdot 10^6 m/s)(4.0\cdot 10^{-4}T)=3.8\cdot 10^{-16}N

8 0
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What is released through nuclear fusion in stars?<br><br> energy<br> gas<br> mass<br> pressure
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Answer:

Energy is released through nuclear fusion

7 0
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