Step-by-step explanation:
not wrong that is super right
Answer:
6
Step-by-step explanation:
4
÷
=
÷
=
* ![\frac{5}{4}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B4%7D)
= ![\frac{120}{20}](https://tex.z-dn.net/?f=%5Cfrac%7B120%7D%7B20%7D)
= 6
Any number that has an additional digit like 0.591 or 0.592 will be greater than 0.59 and have 5 in the tenths place.
I'm going to assume the 4 and 3 are exponents and the expression is
.
The first step is to separate the coefficients of 3 and -6 from the variables and to multiply those as normal:
![3 \cdot (-6) = -18](https://tex.z-dn.net/?f=3%20%5Ccdot%20%28-6%29%20%3D%20-18)
As for the variables, you want to recognize that
means
and
means
, so
![a^4 \cdot a^3 = \left( a \cdot a \cdot a \cdot a\right) \cdot \left(a \cdot a \cdot a\right)](https://tex.z-dn.net/?f=a%5E4%20%5Ccdot%20a%5E3%20%3D%20%5Cleft%28%20a%20%5Ccdot%20a%20%5Ccdot%20a%20%5Ccdot%20a%5Cright%29%20%5Ccdot%20%5Cleft%28a%20%5Ccdot%20a%20%5Ccdot%20a%5Cright%29)
In total, there are 7 a's being multiplied, so
![a^4 \cdot a^3 = a^{4+3} = a^7](https://tex.z-dn.net/?f=a%5E4%20%5Ccdot%20a%5E3%20%3D%20a%5E%7B4%2B3%7D%20%3D%20a%5E7)
Putting this all together, we have:
![\left(3a^4\right)\left(-6a^3\right) = 18a^7](https://tex.z-dn.net/?f=%5Cleft%283a%5E4%5Cright%29%5Cleft%28-6a%5E3%5Cright%29%20%3D%2018a%5E7)
Answer:
![\boxed{Domain = \{3,6,9\}}](https://tex.z-dn.net/?f=%5Cboxed%7BDomain%20%3D%20%5C%7B3%2C6%2C9%5C%7D%7D)
![\boxed{Range = \{9,18\}}](https://tex.z-dn.net/?f=%5Cboxed%7BRange%20%3D%20%5C%7B9%2C18%5C%7D%7D)
Step-by-step explanation:
The relation is:
=> {(3,9)(3,18)(6,18)(9,18)}
Domain => x inputs of the ordered pair
Domain = {3,6,9}
Range => y inputs of the ordered pair
Range = {9,18}