Question

Solve for all possible values of x. VX-9+4= 8

Answer 1

$\sqrt{x-9}+4=8$

$\sqrt{x-9}=8-4$

$\sqrt{x-9}=4$

Put ^2 in both sides

$\sqrt{x-9}^2=4^2$

$x-9=16$

$x=16+9$

$x=25$