Question

A car travels in the +x-direction on a straight and level road. For the first 3.00 s of its motion, the average velocity of the car is υav−x = 6.31 m/s .
How far does the car travel in 4.00s?

Answer 1

Answer:

25.24 m

Explanation:

We are given that a car travels in the positive x direction on  a straight and level road.

We have to find the distance travel by car in 4 s.

Average velocity of car=6.31 m/s

Time =3 s

Distance traveled by the car in 3 sec=$velocity\times time$

Distance traveled by the  car  in 3 sec=$6.31\times 3=18.93 m$

Distance traveled by the car in 1 sec=6.93 m

Distance traveled by the car in 4 sec=$6.93\times 4=25.24 m$

Hence,distance traveled by the car in 4 sec=25.24 m