Which best describes a material that could be used as a pan for baking cakes?

Match the story events on the left to the correct element of plot structure on the right

quester [9]

<u>Explanation:</u>

- Victor pretends he can speak French > Rising action.

- Victor gets his school schedule > Exposition.

- Victor tries to get Teresa's attention after homeroom and at lunch > Rising action.

- Teresa asks Victor if he will help her in French > Falling action.

- Victor checks out books to learn French and help Teresa > Climax

5 0

3 years ago

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A record turntable is rotating at 33 rev/min. A watermelon seed is on the turntable 2.3 cm from the axis of rotation. (a) Calcul

VLD [36.1K]

Answer:

a) $a_{r} = 0.275\,\frac{m}{s^{2}}$ , b) $\mu_{s} = 0.028$ , c) $\mu_{s} = 0.036$

Explanation:

a) The linear acceleration of the watermelon seed is:

$a_{r} = \omega^{2}\cdot r$

$a_{r} = \left[\left(33\,\frac{rev}{min} \right)\cdot \left(2\pi\,\frac{rad}{rev} \right)\cdot \left(\frac{1}{60}\,\frac{min}{s} \right)\right]^{2}\cdot (0.023\,m)$

$a_{r} = 0.275\,\frac{m}{s^{2}}$

b) The watermelon seed is experimenting a centrifugal acceleration. The coefficient of static friction between the seed and the turntable is calculated by the Newton's Laws:

$\Sigma F = \mu_{s}\cdot m\cdot g = m\cdot a$

$a = \mu_{s}\cdot g$

$\mu_{s} = \frac{a}{g}$

$\mu_{s} = \frac{0.275\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$\mu_{s} = 0.028$

c) Angular acceleration experimented by the turntable is:

$\alpha = \frac{\omega-\omega_{o}}{\Delta t}$

$\alpha = \frac{3.456\,\frac{rad}{s}-0\,\frac{rad}{s} }{0.36\,s}$

$\alpha = 9.6\,\frac{rad}{s^{2}}$

The tangential acceleration experimented by the watermelon seed is:

$a_{t} = \left(9.6\,\frac{rad}{s^{2}} \right)\cdot (0.023\,m)$

$a_{t} = 0.221\,\frac{m}{s^{2}}$

The linear acceleration experimented by the watermelon seed is:

$a = \sqrt{a_{t}^{2}+a_{r}^{2}}$

$a = \sqrt{\left(0.221\,\frac{m}{s^{2}} \right)^{2}+\left(0.275\,\frac{m}{s^{2}} \right)^{2}}$

$a = 0.353\,\frac{m}{s^{2}}$

The minimum coefficient of static friction is:

$\mu_{s} = \frac{0.353\,\frac{m}{s^{2}} }{9.807\,\frac{m}{s^{2}} }$

$\mu_{s} = 0.036$

4 0

3 years ago

Kilos pa iskapi halimbawa

Firlakuza [10]

Answer:

Step by step explanation:

7 0

3 years ago

Read 2 more answers

Please please help

dsp73

Answer:

true

Explanation:

The law of conservation of charge states that whenever electrons are transferred between objects, the total charge remains the same.

3 0

4 years ago

Can anyone explain how to do this to me? It is due tomorrow at 9:30am. Thanks.

Georgia [21]

The 102N acting on the ropes being pulled by eric and kim have some of that force acting horizontally, and some of it vertically. By visualizing it as a right angled triangle, with the hypotenuse the length of the diagonal force, and each side the length of the horizontal and vertical forces, you can use trigonometry to calculate the length of the vertical force. You are told that it is at an angle of 30 with the vertical rope, therefore you know the length of the hypotenuse, and the angle between it and the vertical force, so using trig: (vertical force=x)
x/102=cos(30)
x=102*cos(30)
x=88.33
Therefore the diagonal ropes give a vertical force of 88.33N, and the centre rope, as it acts vertically, gives a vertical force of all 102N. The total:
88.33*2+102=278.66N

I don't know if this is very clear, I hope its good enough to help. If you don't understand, just ask, and I can answer any questions!!! :)

3 0

4 years ago