Answer:
a) a = 3.72 m / s², b) a = -18.75 m / s²
Explanation:
a) Let's use kinematics to find the acceleration before the collision
v = v₀ + at
as part of rest the v₀ = 0
a = v / t
Let's reduce the magnitudes to the SI system
v = 115 km / h (1000 m / 1km) (1h / 3600s)
v = 31.94 m / s
v₂ = 60 km / h = 16.66 m / s
l
et's calculate
a = 31.94 / 8.58
a = 3.72 m / s²
b) For the operational average during the collision let's use the relationship between momentum and momentum
I = Δp
F Δt = m v_f - m v₀
F = 
F = m [16.66 - 31.94] / 0.815
F = m (-18.75)
Having the force let's use Newton's second law
F = m a
-18.75 m = m a
a = -18.75 m / s²
The answer is to this question D
The charge experiences no magnetic force when it is moving to the left or to the right
Explanation:
The force experienced by a charge moving in a magnetic field is given by the equation
where
q is the magnitude of the charge
v is its velocity
B is the strength of the magnetic field
is the angle between the directions of v and B
From the equation, we observe that:
- The force is zero when the charge is moving parallel (or anti-parallel) to the field, so when the angle between v and B is zero (or 180 degrees):
(
- The force is maximum when the charge is moving perpendicular to the field, so when the angle between v and B is 90 degrees:
From the first observation, we can say therefore that the charge in the problem will experience no magnetic force when it is moving parallel (or anti-parallel) to the field. Since the magnetic field points to the left, this means that the charge will experience no force when it is moving in one of the following directions:
Learn more about magnetic fields:
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Answer:
v = 3.81 m/s
Explanation:
First, we will find out the radius (r)
sinΘ = r / L
or
r = LsinΘ
on substituting the values, we get
r = 1.2 × sin18°
or
r = 0.370 m
Now,
The tension (T) can be calculated as
ΣF(y) = 0
or
Tcos18° - mg = 0
or
T = mg / cos18.8°
on substituting the values, we have
T = (2kg x 9.8m/s²) / cos18°
or
T = 20.60 N
Now, applying the equilibrium condition in horizontal direction. we have
also, the centripetal acceleration 
on substituting the values, we get
m(v² / r) = Tsin18°
v = (rTsin18° / m)
v = [(1.2m)(20.60 × sin18°) / 2kg]
v = 3.81 m/s
Answer:
a barometer is used to measure atmospheric pressure, and a manometer is used to measure gauge pressure.
Explanation:
A barometer measures air pressure at any locality with sea level as the reference.
However, a manometer is used to measure all pressures especially gauge pressures. Thus, if the aim is to measure the pressure at any point below a fluid surface, a barometer is used to determine the air pressure. The manometer may now be used to determine the gauge pressure
The algebraic sum of these two values gives the absolute pressure.
