If we approximate the rack to be completely flat and the racecar is travelling a constant 30.5 m/s around the turn, what forces
1 answer:
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Answer:
<h2>50 N</h2>Explanation:
The force required can be found by using the formula
w is the workdone
d is the distance
From the question we have
We have the final answer as
<h3>50 N</h3>Hope this helps you
Answer:
W = 55.12 J
Explanation:
Given,
Natural length = 6 in
Force = 4 lb, stretched length = 8.4 in
We know,
F = k x
k is spring constant
4 = k (8.4-6)
k = 1.67 lb/in
Work done to stretch the spring to 10.1 in.
W = 55.12 J
Work done in stretching spring from 6 in to 10.1 in is equal to 55.12 J.