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myrzilka [38]
2 years ago
14

If we approximate the rack to be completely flat and the racecar is travelling a constant 30.5 m/s around the turn, what forces

are responsible for the centripetal acceleration?
Physics
1 answer:
WITCHER [35]2 years ago
3 0

We have,

The race car is travelling a constant 30.5 m/s around the turn. When the car is travelling around a turn, the centripetal force acts on it. The centripetal force is balanced by the force of friction between the car and the surface. Hence, frictional force is responsible for the centripetal acceleration.

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Explanation:

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the height reached is = 0.458 [m]

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Replacing the values on the equation we have:

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Ek=Ep\\where\\Ep=potential energy [J]\\Ep=m*g*h\\where\\g=gravity = 9.81[m/s^2]\\h=height reached [m]\\

Now we have:

h=\frac{Ep}{m*g} \\h=\frac{9}{2*9.81} \\\\h=0.45 [m]

In that moment when the ball reach the 0.45 [m] the potencial energy will be maximum and equal to the kinetic energy when the ball has a velocity of 3[m/s]

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