Answer:
Yes, is should work
Explanation:
USB is widely adopted and supports both forward and backward compatibility. The USB 3.0 printer should work with the USB 2.0 computer. However, having a connection like this, the printer will only be able to work at the speeds of the computer’s USB 2.0. By default, USB is built to allow transfer speeds improvement with upgrades from previous generations while still maintaining compatibility between devices that are supported by them.
Answer:
<u>VLANs</u>
Explanation:
Virtual LANs (VLANs) are a type of network connection or arrangement of network devices in the same broadcast domain. They are called Virtual LANs because they represent fractions or subgroups in the switch ports found in an Ethernet LAN.
Indeed, because of their topological arrangement, this reduces the security risk of unauthorized access to sensitive data or devices since the host can be placed on a different VLAN. Hence, in this scenario, using this network feature would allow visitors to plug into these ports to gain internet access, but they would not have access to any other devices on the private network.
Using the computer language in python to write a function code that personalized house signs
<h3>Writting the code in python:</h3>
<em>#Assign varibles</em>
<em>charge = 0.00</em>
<em>numChars = 8</em>
<em>color = "gold"</em>
<em>woodType = "oak"</em>
<em />
<em>#Checking for number of characters</em>
<em>if numChars > 5:</em>
<em>charge = 35 + (numChars-5)*4</em>
<em>elif numChars > 0:</em>
<em>charge = 35</em>
<em />
<em>#Checking wood type</em>
<em>if woodType == "oak":</em>
<em>charge += 20</em>
<em />
<em>#Checking for color</em>
<em>if color == "gold":</em>
<em>charge += 15</em>
<em />
<em>#Print output</em>
<em>print("The charge for this sign is $"+str(charge)+".")</em>
See more about python at brainly.com/question/13437928
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Solution:
initial = float(eval(input('Enter the monthly saving amount: ')))
x = (1 + 0.00417)
month_one = initial * x
month_two = (initial + month_one) * x
month_three = (initial + month_two) * x
month_four = (initial + month_three) * x
month_five = (initial + month_four) * x
month_six = (initial + month_five) * x
print('The sixth month value is: '+str(month_six))
Don't forget the saving amount, and initialize the balance with that amount. Inside the loop, work out and add the interest and then add the saving amount for the next month.
balance = 801
for month in range(6):
balance = balance * (1.00417)
print(balance)
