This is a quadratic equation whose graph is a parabola that opens down.
When does the rocket reach its highest point? Note that at that point it will stop ascending, momentarily stop, and then begin descending. Note also that that point is the vertex of the parabola.
The easiest way to find that time value is to use the formula t = -b/(2a).
Here, t at max height is t = -(144) / (2*[-16]) = 4.5 sec (answer.
What's the rocket's height there? To answer this, sub 4.5 sec for t in the given equation, <span>h(t) = -16t^2 + 144t.
Note: Please use " ^ " to indicate exponentiation:
</span> -16t^2 + 144t (not -16t2 + 144t)
Answer:it’s B aka 3
Step-by-step explanation:
Hey there! :)
Answer:
C. (0, -6).
Step-by-step explanation:
In slope-intercept form ( y = mx + b), the 'b' value represents the y-intercept.
In this instance:
y = 4x - 6
The 'b' value is equal to -6. This means that the y-intercept is at (0, -6).
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The y-intercept can also be solved for by substituting in 0 for x:
y = 4(0) - 6
y = 0 - 6
y = -6.
Answer:
Question #2: Option B, b
Question #3: Option A, x(2x - 6y)
Step-by-step explanation:
<u>Question #2</u>
The GCF of b^2 and b is b
Answer: Option B, b
<u>Question #3</u>
The answer is Option A, since it distributes as 2x^2 - 6xy
Answer: Option A, x(2x - 6y)
7 x 6 is 42 hope that helps