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ratelena [41]
2 years ago
11

Find the equation of the line that is parallel to the line y=-3/2 x+4 and passes through the point (4,0)

Mathematics
1 answer:
guajiro [1.7K]2 years ago
3 0
The answer is y=(-3/2)x+6

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PLZ HELP WILL GIVE BRAINLY IF CORRECT
pochemuha

Answer:

1000 MM is the greatest

Step-by-step explanation:

1000 MM to CM = 100

9.7 CM and 4.7 CM are too small, therefore, we ignore them..

450 MM to CM is 45, therefore 1000 MM is the greater length

3 0
2 years ago
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Two spherical shells have their mass uniformly distrubuted over the spherical surface. One of the shells has a diameter of 2 met
ivann1987 [24]
The moment of inertia of a spherical shell is I = mr²

If two spheres have the same moment of inertia, then
I₁ = I₂
m₁(r₁)² = m₂(r₂)²

Solve for the second mass:
m₂ = m₁ (r₁/r₂)²

Given m₁ = 1 kg, r₁ = 2 m, r₂ = 1m,
m₂ = (1 kg) (2 m / 1 m)² = 4 kg

7 0
2 years ago
Solve for s.<br> -7 = 7s + 28
Zinaida [17]

Answer:

s=  -5

Step-by-step explanation:

have a good day

6 0
2 years ago
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12345 what is the answer if you multiply 1x2x3x4x5 and do the same with subtraction, addition and devision, in that order. Then
Alexandra [31]

Well, we just need to perform the operations:

  • Multiplication: 1\cdot 2 \cdot 3 \cdot 4 \cdot 5 = 120
  • Subtraction: 1-2-3-4-5 = -13
  • Addition: 1+2+3+4+5 = 15
  • Division: 1 \div 2 \div 3 \div 4 \div 5 = \frac{1}{120}

So, if you add all the numbers together you get

120-13+15+\dfrac{1}{120} = 122 + \dfrac{1}{120}

Or, if you prefer,

\dfrac{1681}{120}

8 0
2 years ago
How many class periods that are 3/4 of an hour-long will fit into 6 3/4 an hour school day? Assume that the class period include
Marrrta [24]

Answer:

about 8 classes

Step-by-step explanation:

convert 6 3/4 to a fraction: 27/4

3/4 can go into 27/4 9 times, but with time in between, you should only be able to have 8 classes instead of 9

8 0
2 years ago
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