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Colt1911 [192]
3 years ago
14

Jerome plays middle linebacker for South's varsity football team. In a game against cross-town rival North, he delivered a hit t

o North's 82-kg running back, changing his eastward velocity of 5.6 m/s into a westward velocity of 2.5 m/s.
Physics
1 answer:
anygoal [31]3 years ago
5 0

Explanation:

We have,

Mass of the running back, m = 82 kg

Initial speed of the running back, u = +5.6 m/s

Final speed of the running back, v = -2.5 m/s

It is required to find the momentum change of the running back. For this we will subtract final momentum to the initial momentum. So,

\Delta p=m(v-u)\\\\\Delta p=82\times (-2.5-5.6)\\\\\Delta p=-664.2\ kg-m/s

So, the magnitude of the change in momentum of the running back is 664.2 m/s in west direction.

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pychu [463]

Answer:

C. 30.6m

Explanation:

To find the height of the tower, we are to use Newtons law of motion to solve this problem. Since the penny is falling from the top of the tower, it is acted by the acceleration due to gravity. The formula to be used is:

H=ut+\frac{1}{2}gt^2

Where H is the height of the tower, t is the time taken to hit the ground, u is the initial velocity and g is the acceleration due to gravity.

Given that, t = 2.5 s, g =9.8 m/s², u = 0 m/s (at the top of tower)

H=ut+\frac{1}{2}gt^2\\\\H=0(2.5)+ \frac{1}{2}(9.8)(2.5)^2\\\\H=30.6\ m

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