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Colt1911 [192]
3 years ago
14

Jerome plays middle linebacker for South's varsity football team. In a game against cross-town rival North, he delivered a hit t

o North's 82-kg running back, changing his eastward velocity of 5.6 m/s into a westward velocity of 2.5 m/s.
Physics
1 answer:
anygoal [31]3 years ago
5 0

Explanation:

We have,

Mass of the running back, m = 82 kg

Initial speed of the running back, u = +5.6 m/s

Final speed of the running back, v = -2.5 m/s

It is required to find the momentum change of the running back. For this we will subtract final momentum to the initial momentum. So,

\Delta p=m(v-u)\\\\\Delta p=82\times (-2.5-5.6)\\\\\Delta p=-664.2\ kg-m/s

So, the magnitude of the change in momentum of the running back is 664.2 m/s in west direction.

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What occurs when human muscle is forced to make ATP without oxygen
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Lactic acid fermentation. hope this helps :)

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4 years ago
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2. A 2,000 kg rocket is launched 12 km straight up at a constant acceleration into the sky at which point the rocket is travelli
Mice21 [21]

Answer:

797700000 J

Explanation:

From the question,

The work done by the rocket, is given as,

W = Ek+Ep............. Equation 1

Where Ek and Ep are the potential and the kinetic energy of the rocket respectively.

Ep = mgh............ Equation 2

Ek = 1/2mv²............. equation 3

Substitute equation 2 and equation 3 into equation 1

W = mgh+1/2mv².............. Equation 4

Where m = mass of the rocket, h = height, v = velocity of the rocket, g = acceleration due to gravity.

Given: m = 2000 kg, h = 12 km = 12000 m, v = 750 m/s, g = 9.8 m/s²

Substitute into equation 4

W = 2000(12000)(9.8)+1/2(2000)(750²)

W = 235200000+562500000

W = 797700000 J

6 0
3 years ago
At the same moment, one rock is thrown upward at 4.5 m/s and another thrown downward at 6.2 m/s. What is the relative velocity o
erastova [34]
The correct answer is 
<span>C) -10.7 m/s 

In fact, the first rock is moving upward with velocity +4.5 m/s, while the second rock is moving downward with velocity -6.2 m/s, with respect to a fixed reference frame. In the reference frame of the first rock, instead, the second rock is moving with velocity equal to its velocity in the fixed frame minus the velocity of the reference frame of the first rock:
</span>v=-6.2 m/s -(+4.5 m/s) = -10.7 m/s<span>
</span>
8 0
4 years ago
NEED HELP ASAP QUIZ PLEASE
zmey [24]
Blank 1 Thermal energy
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Thermal energy is the total energy of the particles.
Heat is the movement of thermal energy from a substance at a higher temperature to another at a lower temperature
6 0
3 years ago
What type of image is formed by a lens if m = -1.6?
anastassius [24]

The image formed from the lens is real, inverted and enlarged

Explanation:

The magnification of a lens is given by:

m=\frac{y'}{y}=-\frac{q}{p} (1)

where:

y' is the size of the image

y is the size of the object

q is the distance of the image from the lens

p is the distance of the object from the lens

For this lens, the magnification is

m = -1.6

We notice the following:

- The magnification is negative

- The magnification is larger than 1

Looking at eq.(1), we can therefore make the following conclusions:

- SInce m=\frac{y'}{y} and |m|>1, it follows that |y'|>|y|, so the image is larger than the object

- Since m=\frac{y'}{y} and m, it follows that y' (since y > 0 for convention): this means that the image is inverted

- Since m=-\frac{q}{p} and m, it follows that q>0 (since p > 0 for convention): this means that the image is real

Learn more about lenses and mirrors here:

brainly.com/question/8737441

#LearnwithBrainly

5 0
3 years ago
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