Answer:
Explanation:
Given
launch velocity 
Launch angle 
Range of Projectile 
Horizontal velocity remain same and only vertical velocity changes.
Initially vertical velocity is in upward direction but as soon as it reaches the ground its direction change but magnitude remain same.
Answer:
24volts
Explanation:
If a 15-µF capacitor is charged to 40V, the charge across the capacitor can be calculated using the formula;
Q = CV where;
Q is the charge flowing across the capacitor
C is the capacitance of the capacitor. = 15-µF
V is the voltage = 40V
Q = 15×10^-6×40
Q = 0.0006coulombs
If the charge of 0.0006coulombs is then connected across an initially uncharged 25-µF capacitor, the potential difference across the 25-µF can be calculated using the initial expression;
Q = CV
V = Q/C
V = 0.0006/25×10^-6
V = 24Volts
Therefore, the final potential difference across the 25-µF capacitor will be 24volts
There is no direct connection between the speed of an object and its potential energy.
UNLESS the object is falling, and it's GETTING its speed FROM its potential energy. If that's what's going on, then of course if the speed increases, the object's kinetic energy increases, and that increase has to come from using up some of the potential energy.
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