Answer:
the frequency of the oscillation is 1.5 Hz
Explanation:
Given;
mass of the spring, m = 1500 kg
extention of the spring, x = 5 mm = 5 x 10⁻³ m
mass of the driver = 68 kg
The weight of the driver is calculated as;
F = mg
F = 68 x 9.8 = 666.4 N
The spring constant, k, is calculated as;
k = F/m
k = (666.4 N) / (5 x 10⁻³ m)
k = 133,280 N/m
The angular speed of the spring is calculated;
The frequency of the oscillation is calculated as;
ω = 2πf
f = ω / 2π
f = (9.426) / (2π)
f = 1.5 Hz
Therefore, the frequency of the oscillation is 1.5 Hz
Answer: The gravitational acceleration on planet X is 5 N/kg
On Earth (with the gravitational accelartion g_E) the mass of 2kg will correspond to
On planet X we are told the same measure is only 10N. Since there is a proportional relationship between g and F, we can calculate g_X:
<span>T(t)=60+140<span>e<span>−0.075t</span></span></span>
<span>T(12)=60+140<span>e<span>−0.075∗12</span></span></span>
<span>T(12)=60+140<span>e<span>−0.9</span></span></span>
<span><span>T(12)=60+140(0.4065696597)
=116.84
So the temperature will be approximately 117 degrees</span></span>
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2 x 3 = 6
Thus there are 6 atoms of oxygen in this molecule.
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- Ally ✧
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Answer:
If it is triple it means we multiply it by 3 then it is 36.3 m/s/s
