1. What is the force of the marble?
For an object near the surface of the earth, the gravitational force acting upon the object is given by:
F = mg
F is the gravitational force, m is the object's mass, and g is the acceleration of objects due to earth's gravity.
Given values:
m = 0.025kg, g = 9.8m/s²
Plug in the given values and solve for F:
F = 0.025×9.8
F = 0.25N
2. What is the marble's potential energy at the start of its fall?
The gravitational potential energy of an object near the earth's surface is given by:
PE = mgh
PE is the potential energy, m is the object's mass, g is the acceleration of objects due to earth's gravity, and h is the object's relative height.
new given values:
h = 0.08m
Since F = mg, you can simply multiply F×h to get PE. Use the result from question 1:
PE = F×h
PE = 0.25×0.08
PE = 0.02J
Answer:
The ampere was chosen as a base unit, because it is easily measured whereas the coloumb is not. Interestingly, there is a move a foot to redefine the ampere (which will remain a base unit) in terms of the fundamental charge on an electron (not in terms of coulomb).
Explanation:
It is wires or the sun from outside the sun as heat which light thing
Answer:
apply ideal gas equation
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