Answer:
Net charge contained in the cubeq= 3.536×10^-6C
Explanation:
Formular for total flux in a cube is given as:
Total flux= E300Acos(180) + E200Acos(0)
Where A is crossectional area
Total flux= A(E200-E300)
Total flux= q/Eo
q= Eo×total flux
q=(8.84×10^-12)×(100)^2×(100-60)
q= 3.536×10^-6C
Answer:
The speed of the laser light in the cable, 
Explanation:
It is given that,
Wavelength of Argon laser, 
Refractive index, n = 1.46
Let
is the speed of the laser light in the cable. The speed of light in a medium is given by :



or

So, the speed of the laser light is
. Hence, this is the required solution.
Answer:

Explanation:
Given:
- mass of nerf projectile,

- velocity of nerf projectile,

- mass of the gun,

Now in this case the collision can be assumed to be perfectly elastic.
<u>For an elastic collision:</u>

where:
recoil velocity of the gun


Answer:
The horizontal component of the vector ≈ -16.06
The vertical component of the vector ≈ 19.15
Explanation:
The magnitude of the vector,
= 25 units
The direction of the vector, θ = 130°
Therefore, we have;
The horizontal component of the vector, Rₓ =
× cos(θ)
∴ Rₓ = 25 × cos(130°) ≈ -16.06
<em>The horizontal component of the vector, Rₓ ≈ -16.06</em>
The vertical component of the vector, R
=
× sin(θ)
∴ R
= 25 × sin(130°) ≈ 19.15
<em>The vertical component of the vector, R</em>
<em> ≈ 19.15</em>
(The vector, R = Rₓ + R
= Rₓ·i + R
·j
∴
≈ -16.07·i + 19.15j)
I’m guessing convection currents since you mention mantle and core, reminds me of heat