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pshichka [43]
3 years ago
15

Help please!! asap!!

Mathematics
1 answer:
Artist 52 [7]3 years ago
3 0

Answer:

I'm pretty sure it is D.

Step-by-step explanation:

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What is the value of x?
Angelina_Jolie [31]

Answer/Step-by-step explanation:

well, first figure out how many units/times prism A was enlarged to become prism B...

16 ÷ 2 = 8

Now if we apply that info to the length of the prism, then...

80 ÷ 8 = 10

Therefore x = 10

And the Prisms remain congruent and proportional!

<h2>Hope this helps!</h2><h2>Please mark Brainliest!!! <em>=D</em></h2>
5 0
3 years ago
Identify the lower class​ limits, upper class​ limits, class​ width, class​ midpoints, and class boundaries for the given freque
Aleks [24]

Step-by-step explanation:

kindly find attached detailed information of the remaining information as requested for your reference

   

1. The lower class limit is the left number in the age column

   i.e in the 25-34 the lower class limit is 25          

2. The upper class limit is the right number in the age column

   i.e in the 25-34 the lower class limit is 34

3. The class width is the difference  between the class boundaries of a single class

 class width = 34.5-24.5= 10

4. The number of individuals is= 29+34+16+3+5+1+2= 90    

7 0
3 years ago
MATLAB Simulation. Develop a Matlab script to simulate the modulation of a 30 kHz carrier with a 0.5 kHz message signal. Use 40%
iren2701 [21]

Answer:

MATLAB code for DSB-SC modulation.

fc=154000; % carrier signal frequency

fm=fc/10; % message signal frequency

fs=100*fc;

t=0:1/fs:4/fm;

xc=cos(2*pi*fc*t);

xm=10*cos(2*pi*fm*t); % amplitude of sinusodial is 10

figure(1)

subplot(2,1,1),plot(t,xc);

title('carrier signal of 154 khz');

xlabel('time (sec)');

ylabel('amplitude');

subplot(2,1,2),plot(t,xm);

title('message signal of 15.4 khz');

xlabel('time (sec)');

ylabel('amplitude');

% DSB-SC MODULATION

z1= xm.*xc;

figure(2)

subplot(2,1,1),plot(t,z1);

title('DSB-SC MODULATION IN TIME DAOMAIN');

xlabel('time (sec)');

ylabel('amplitude');

l1=length(z1);

f=linspace(-fs/2,fs/2,l1);

Z1=fftshift(fft(z1,l1)/l1);

subplot(2,1,2),plot(f,abs(Z1));

title('DSB SC MODULATION IN FREQUENCY DOMAIN');

xlabel('frequency(hz)');

ylabel('amplitude');

axis([-200000 200000 0 3]);

Step-by-step explanation:

6 0
3 years ago
¿Decir al cuadrado el lo mismo que decir elevado a la 2?
scoundrel [369]
Hola ,  decir al cuadrado es lo mismo que decir elevado a la 2.
5 0
3 years ago
Sebastian studies from 3:15 - 4:45 p.m his sister,Sara studies from 4:30 -6:15 p.m who studies longer and by how,much?
3241004551 [841]

Answer:

Sara studied longer.

She studied longer by 15 minutes.

Step-by-step explanation:

Sebastian:- 3:15 - 4:45p.m

Sara :- 4:30 - 6:15p.m

For how long did Sebastian study?

4:45

-3:15

1:30

Proof:

1:30

+3:15

4:45

Sebastian studied for an hour and 30 minutes.

For how long did Sara study?

6:15

-4:30

1:45

Proof:

6:15 to min=375

4:30 to min=270

375-270=105

105 min to hour=1:45

Hope this helps ;) ❤❤❤

3 0
4 years ago
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