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pshichka [43]
2 years ago
15

Help please!! asap!!

Mathematics
1 answer:
Artist 52 [7]2 years ago
3 0

Answer:

I'm pretty sure it is D.

Step-by-step explanation:

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Fill in the blank to make the fractions equivalent 2/3 = Blank/15
kotegsom [21]
Answer: 2/3 = 10/15
8 0
2 years ago
A $1,200 computer is losing value at a rate of 22% per year; 2 years​
zalisa [80]

Answer:

$730.08

Step-by-step explanation:

22% = 0.22

1 - 0.22 = 0.78

Value after 2 years

v = 1200(0.78)²

v = 730.08

$730.08

6 0
2 years ago
Gannon has deposited $742 in a savings account that earns interest at a rate of 3.4% compounded monthly. What will the account b
marta [7]
Firstly, solve the effective annual interest (ieff) with the equation,
 
                          ieff = (1 + i/m)^m -1

where i is the interest rate and m is the number of times the interest is compounded in a year. In this problem, m is 12

Substituting the values, 
                            ieff = (1 + 0.034/12)^12 - 1 =0.03453

To solve for the future (F) amount of the present investment (P), 
                                       
                                        F = P x (1 + ieff)^n

where n is number of years.
 
                                        F = ($742) x (1 + 0.03453)^15

Thus, the answer is $1234.76. 


 
                

7 0
3 years ago
Create and solve a 2 step equation with addition and division.
Inessa05 [86]

Answer:

(2+4)÷12

Step-by-step explanation:

jxkgxljcluckyxlhlusgibibsi do u need an explanation but here

6 0
3 years ago
Prove the following statements: (a) For every integer x, if x is even, then for every integer y, xy is even. (b) For every integ
Murrr4er [49]

Answer and Step-by-step explanation:

(a) Given that x and y is even, we want to prove that xy is also even.

For x and y to be even, x and y have to be a multiple of 2. Let x = 2k and y = 2p where k and p are real numbers. xy = 2k x 2p = 4kp = 2(2kp). The product is a multiple of 2, this means the number is also even. Hence xy is even when x and y are even.

(b) in reality, if an odd number multiplies and odd number, the result is also an odd number. Therefore, the question is wrong. I assume they wanted to ask for the proof that the product is also odd. If that's the case, then this is the proof:

Given that x and y are odd, we want to prove that xy is odd. For x and y to be odd, they have to be multiples of 2 with 1 added to it. Therefore, suppose x = 2k + 1 and y = 2p + 1 then xy = (2k + 1)(2p + 1) = 4kp + 2k + 2p + 1 = 2(kp + k + p) + 1. Let kp + k + p = q, then we have 2q + 1 which is also odd.

(c) Given that x is odd we want to prove that 3x is also odd. Firstly, we've proven above that xy is odd if x and y are odd. 3 is an odd number and we are told that x is odd. Therefore it follows from the second proof that 3x is also odd.

3 0
3 years ago
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