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Leto [7]
3 years ago
11

Solve the equation:39 = 3m - 12​

Mathematics
2 answers:
bogdanovich [222]3 years ago
5 0

Answer:

17

Step-by-step explanation:

39 + 12 = 51

51 divided by 3 = 17

This means that 17 x 3 = 51

51 - 12 = 39

Fed [463]3 years ago
3 0

Answer: m = 17

Step-by-step explanation:

3m = 39+12

3m = 51

m = 17

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4 friends evenly divided up an n-slice pizza. One of the friends, Harris, ate 1 fewer slice than he received.
ivann1987 [24]

Answer:

4 friends evenly divided up a n -slice pizza.

So, the number of slices each friend received = n/4

Now, Harrison ate 1 fewer slice than he received. As he received n/4 slices, so 1 fewer than n/4 means......

Harrison ate n/4-1 slices of pizza.

Step-by-step explanation:

6 0
1 year ago
Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
a ladder that is 20 feet long is leaning against the side of a building if the angle formed between the ladder and the ground is
Mademuasel [1]

Answer:

Step-by-step explanation:

Take 20( cosine of 75 degrees)

the answer is 5 ft

8 0
3 years ago
Read 2 more answers
How do you find the radius of a circle with a circumference of 12pi
sergejj [24]

Answer:

6

Step-by-step explanation:

The circumference of a circle is 2\pir\pi r, so 12\pi=2\pi r\\12=2r\\r=6.  We can use this because the area of a circle is \pi r^2.  Thus, \pi*6^2=36\pi.

4 0
3 years ago
3=c/5+2... how do I solve for c??
expeople1 [14]
Primeiro Você IRA Dividir o c (APENAS Colocar 5 + 2 embaixo do c). Depois faça a soma 5 + 2 = 7. Então faça o mmc (mínimo múltiplo comum) entre 7 e 1(o 1 é invisível, mas continua estando embaixo do 3). Deu 7 o mmc. Transforme seus números em frações, com o denominador 7. Transforme os números em frações o 3 virá 21, pois você divide em baixo e multiplica em baixo, e o c continua normal, pois já estava em baixo de 7. Como é para descobrir uma incógnita você tira os denominadores e ficará 21 = c.

3 = c/5 + 2
3 = c/7
21/7 = c/7
21 = c
4 0
2 years ago
Read 2 more answers
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