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tatyana61 [14]
3 years ago
12

Is this one question correct

Mathematics
1 answer:
bazaltina [42]3 years ago
7 0

Answer: 2/3ft or C

Step-by-step explanation: Solve for b in the area of a triangle equation, A=1/2bh. Multiply 1/2 by 2 on both sides to cancel it: A(2)=bh.  Divide both sides by h: \frac{A(2)}{h}=b

A = 2/5

h = 6/5

b = ?

Next, we can plug the numbers into this equation: \frac{2/5(2)}{6/5}=b

Multiply 2 and 2/5: 4/5 / 6/5

Take the reciprocal of 6/5: 4/5 x 5/6 = \frac{20}{30}

\frac{20}{30} ÷ \frac{10}{10} = \frac{2}{3}

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FInd the length of DB and CD. Please help!
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Step-by-step explanation:

DB length = 5 1/4 + 2/3

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3 years ago
How large a sample should be selected to provide a 95% confidence interval with a margin of error of 6? Assume that the populati
marshall27 [118]

Using the z-distribution, it is found that a sample of 171 should be selected.

<h3>What is a z-distribution confidence interval?</h3>

The confidence interval is:

\overline{x} \pm z\frac{\sigma}{\sqrt{n}}

The margin of error is:

M = z\frac{\sigma}{\sqrt{n}}

In which:

  • \overline{x} is the sample mean.
  • z is the critical value.
  • n is the sample size.
  • \sigma is the standard deviation for the population.

For this problem, the parameters are:

z = 1.96, \sigma = 40, M = 6

Hence we solve for n to find the needed sample size.

M = z\frac{\sigma}{\sqrt{n}}

6 = 1.96\frac{40}{\sqrt{n}}

6\sqrt{n} = 40 \times 1.96

\sqrt{n} = \frac{40 \times 1.96}{6}

(\sqrt{n})^2 = \left(\frac{40 \times 1.96}{6}\right)^2

n = 170.7.

Rounding up, a sample of 171 should be selected.

More can be learned about the z-distribution at brainly.com/question/25890103

#SPJ1

4 0
2 years ago
Please help me with this sum​
barxatty [35]

Answers:

781 × 8 = 6248

231 × 7 = 1617

421 × 6 = 2526

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951 × 4 = 3804

741 × 3 = 2223

361 × 3 = 1083

931 × 7 = 6517

821 × 2 = 1642

8 0
2 years ago
What is the simplest form of 3(0.44r-2.1)-2.1(r-0.3)
netineya [11]

Answer:

−0.78r − 5.67

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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