All you can conclude is that something must be burning with an orange flame.
Actually, the "something" that must be burning is the hydrogen that is produced when the sodium reacts with the water:
2Na + 2H₂O → 2NaOH + H₂ + heat
So much heat is produced that the hydrogen catches fire and some of the sodium evaporates into the flame.
The electrons in the sodium atoms get "excited" in the flame. When they drop back to a lower energy level, they emit energy in the form of an orange-yellow light.
Answer:
106 mL
Explanation:
In order to be able to answer this question, you must understand what the density of a substance tells you.
The density of a substance is nothing more than the mass of that substance that occupies one unit of volume.
In your case, the density of ethanol is given in Grams per milliliter, which means that one unit of volume will be
1 mL
.
So, ethanol has a density of
0.785 g mL
−
1
, which is equivalent to saying that if you take exactly
1 mL
of ethanol and weigh it, you will end up with a mass of
0.785 g
.
Now, you know that the volume you're using has a mass of
83.3 g
. Well, if you get
0.785 g
for every
1 mL
of ethanol, it follows that this much mass will correspond to a volume of
83.3
g ethanol
⋅
ethanol's density
1 mL
0.785
g ethanol
=
106.11 mL
Rounded to three sig figs, the answer will be
V
ethanol
=
106 mL
Hope this helps
Answer:
Kp is 0.228/atm
Explanation:
This is the reaction:
CO + Cl<u>₂</u> → CCl₂O
1 mol of carbon monoxide and 1 mol of chlorine produce 1 mol of phosgene.
Formula for Kp which derivates from Kc is:
Kp = Kc (R.T)ⁿᵇ ⁻ ⁿᵃ
Δп = nb (moles in the products) - nₐ(moles in the reactants)
Δп = 1 - 2 = -1
T is T° in K → T°C + 273 = 611°C +273 = 884K
R → Universal constant gas → 0.082 L.atm/mol.K
We replace the data: Kp = 16.5 L/mol (0.082 . 884K)⁻¹ → 0.228/atm
<h3>
Answer:</h3>
54 g
<h3>
Explanation:</h3>
- The reaction between carbon and oxygen gas is given by the equation;
C(s) + O₂(g) → CO₂(g)
We are given;
18 g of Carbon
72 g of Carbon dioxide
- We need to calculate the amount of oxygen needed for the reaction.
- From the law of conservation of mass in chemical equation, the mass of the reactants is equal to the mass of the product.
Therefore;
Mass of Oxygen gas + mass of the carbon = Mass of carbon dioxide
Therefore;
Mass of Oxygen gas = mass of carbon dioxide - mass of carbon
= 72 g - 18 g
= 54 g
Therefore, the mass of Oxygen needed would be 54 g
