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4 years ago

Question 7 of 32

Chemistry

2 answers:

Sever21 [200]4 years ago

3 0

Answer:O D to protect the environment from harmful chemicals

Explanation:

ASHA 777 [7]4 years ago

3 0

D.) to protect the environment from harmful chemicals

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Given the following balanced equation, determine the rate of reaction with respect to [O2]. If the rate of formation of O2 is 7.

murzikaleks [220]

Answer: The rate of the loss of $O_3$ is 0.52M/s

Explanation:

Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

The rate in terms of reactants is given as negative as the concentration of reactants is decreasing with time whereas the rate in terms of products is given as positive as the concentration of products is increasing with time.

$2O_3(g)\rightleftharpoons 3O_2(g)$

Rate of disappearance of $O_3$ = $-\frac{1d[O_3]}{2dt}$

Rate of formation of $O_2$ = $+\frac{1d[O_2]}{3dt}$

$-\frac{1d[O_3]}{2dt}=+\frac{1d[O_2]}{3dt}$

Rate of formation of $O_2$ = $7.78\times 10^{-1}M/s$

Thus Rate of disappearance of $O_3$ = $\frac{2d[O_2]}{3dt}=\frac{2}{3}\times 7.78\times 10^{-1}M/s=0.52M/s$

8 0

4 years ago

If the smallest markings on a ruler are one tenth (1/10) of a centimeter, which of the following measurements could be recorded

makkiz [27]

I think it should be A

4 0

4 years ago

Read 2 more answers

A gaseous fuel mixture stored at 747 mmHg and 298 K contains only methane (CH4) and propane (C3H8). When 11.1 L of this fuel mix

Alisiya [41]

Answer:

$M_f=38.8\%$

Explanation:

From the question we are told that:

Pressure $P=747mmHg$

Temperature $T=298K$

Volume $V=11.1$

Heat Produced $Q=780kJ$

Generally the equation for ideal gas is mathematically given by

$PV=nRT$

$n= (747/760) *11.1/ (0.0821*298)$

$n=0.446mol$

Therefore

$x+y=0.446$

$x=0.446-y .....1$

Since

Heat of combustion of Methane=889 kJ/mol

Heat of combustion of Propane=2220 kJ/mol

Therefore

$x(889) + y(2220) = 760 ...... 2$

Comparing Equation 1 and 2 and solving simultaneously

$x=0.446-y .....1$

$x(889) + y(2220) = 760 ...... 2$

$x=0.173$

$y=0.273$

Therefore

Mole fraction 0f Methane is mathematically given as

$M_f=\frac{x}{n}*100\%$

$M_f=\frac{1.173}{0.446}*100\%$

$M_f=38.8\%$

7 0

3 years ago

HELP PLEASEEE <br>it's for an exam on monday

zhannawk [14.2K]

From the stoichiometry of the reaction, we can see that the volume of carbon monoxide reacted is 44.8 L.

<h3>What is stoichiometry?</h3>

Stoichiometry is used to obtain the amount of substance reacted or the amount of product formed.

Number of moles of CO2 in 88g = 88g/4 g/mol = 2 moles

Molar mass of carbon monoxide = 12 + 16 = 28g/mol

We can see that 1 mole of oxygen was used in the reaction hence the mass of oxygen used is 32 g/mol. Given the stoichiometry of the reaction, 28g of carbon monoxide was burned.

If 1 mole of a gas occupies 22.4 L

2 moles of a gas occupies 2 moles * 22.4 L/1 mole

= 44.8 L

Learn more about stoichiometry:brainly.com/question/9743981

#SPJ1

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3 years ago

What are some disadvantages of incinerators?

madreJ [45]

Well... In this case.. They burn bodies..

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3 years ago