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CaHeK987 [17]
3 years ago
14

Which statement about the greenhouse effect is NOT true?

Chemistry
1 answer:
Archy [21]3 years ago
7 0
<span> Greenhouse gases were not historically present in the atmosphere.</span>
You might be interested in
Determine the freezing point of a 0.51 molal
Elan Coil [88]

Answer:

-65.897°C.

Explanation:

  • Adding solute to water causes depression of the boiling point.
  • The depression in freezing point (ΔTf) can be calculated using the relation: <em>ΔTf = Kf.m,</em>

where, ΔTf is the depression in freezing point of chloroform solution.

Kf is the molal depression constant of chloroform (Kf = 4.70°C.kg/mol).

m is the molality of the solution (m = 0.51 m).

∴ ΔTf = Kf.m = (4.70°C.kg/mol)(0.51 m) = 2.397°C.

∴ The freezing point of the solution = (freezing point of chloroform) - ΔTf = (-63.5°C) - (2.397°C) = -65.897°C.

7 0
3 years ago
A liquid that occupies a volume of 8.2 L has a mass of 5.6 kg ehat is the density of the liquid in kg/l
BaLLatris [955]
Hey there!

Mass = 5.6 Kg

Volume =8.2 L

D = m / V

D = 5.6 / 8.2

D = 0.6829 Kg/L

hope this helps!
4 0
3 years ago
Read 2 more answers
How many daltons is in an ion with 15 protons, 16 neutrons and 17 electrons?
Vera_Pavlovna [14]
31  
A dalton is the same as an atomic mass unit. And an atomic mass unit is approximately the mass of a nucleon (proton or neutron) such that the mass is 1 g/mol. So in this problem you have 15 protons and 16 neutrons, so the number of daltons is 15 + 16 = 31.
8 0
3 years ago
A sample of 0.0860 g of sodium chloride is added to 30.0 mL of 0.050 M silver nitrate, resulting in the formation of a precipita
mestny [16]

Answer:

The answer is:

(a) NaCl(aq)+AgNO_3(aq) \rightarrow AgCl(r) +NaNO_3 (aq)

(b) NaCl

(c) 0.211 g

Explanation:

Given:

The mass of NaCl,

= 0.0860 g

The molar mass of NaCl,

= 58.44 g/mol

The volume of AgNO_3,

= 30.0 ml

or,

= 0.030 L

Molarity of AgNO_3,

= 0.050 M

Moles of NaCl will be:

= \frac{Given \ mass}{Molar \ mass}

= \frac{0.0860}{58.44}

= 0.00147 \ mol

now,

Moles of AgNO_3 will be:

= Molarity\times Volume

= 0.050\times 0.030

=0.0015 \ mol

(a)

The reaction is:

⇒ NaCl(aq)+AgNO_3(aq) \rightarrow AgCl(r) +NaNO_3 (aq)

(b)

1 mole of NaCl react with,

= 1 mol of AgNO_3

0.0015 mol AgNO_3 needs,

= 0.00150 \ mol \ NaCl

Available mol of NaCl < needed amount of NaCl

So,

The limiting reagent is "NaCl".

(c)

The precipitate formed,

= 0.00147\times \frac{1}{1}\times \frac{143.32}{1}

= 0.211 \ g \ AgCl

4 0
3 years ago
Write the correct name of the Fe(CIO3)3​
pychu [463]

Answer:

Iron(III) Chlorate Fe(ClO3)3 Molecular Weight

Explanation:

3 0
2 years ago
Read 2 more answers
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