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andreev551 [17]
4 years ago
14

Positive feedback interactions in earth’s systems are always a result of human action. T/F

Physics
1 answer:
VLD [36.1K]4 years ago
4 0

Positive feedback interactions in earth’s systems are always a result of human action is a FALSE statement.

<u>Explanation:</u>

Earth is a unstable equilibrium which tends to move out of equilibrium, but several other factors try to bring it back in equilibrium again. Earth has a different actions going on both on its surface and also inside it.

Human can alter, or can modify a very small part of the events that occur on earth’s surface. But they don’t have any control on what’s going inside earth’s core. So positive feedback interactions are not only the results of human interaction, but also different other factors.  

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A golfer tees off from the top of a rise, giving the golf ball an initial velocity of 44 m/s at an angle of 25° above the horizo
mars1129 [50]

Answer:

a) y=17.6m

b) v_{x}=39.87m/s\\v_{y}=-28.05m/s

Explanation:

From the exercise we got our <u>initial data</u>

v_{o}=44m/s\\\beta =25\\x=190m

a) To find <u><em>maximum height</em></u> we know that at that point v_{y}=0

v_{y} ^{2} =v_{oy} ^{2} +2a(y-y_{o} )

0=(44sin25)^{2} -2(9.8)y

Solving for y

y=\frac{(44sin25)^{2} }{2(9.8)} =17.6 m/s

b) Since we know that the ball strikes the fairway 190 m away

x=v_{ox}t\\ 190=44cos25t

Solving for t

t=4.76s

Now, we can calculate the speed of the ball in both axes

v_{x}=44cos25=39.87m/s

v_{y}=v_{oy}+at

v_{y}=44sin25-(9.8)(4.76)=-28.05m/s

The <em>negative</em> sign means the direction of the ball at that point.

5 0
4 years ago
An object with a mass of 3 kg has a momentum of 75 kg.m/s. What is its velocity?
tiny-mole [99]

Answer:

25m/s

Explanation:

p=mv

75 = 3v

v = 75/3

v = 25 m/s

If you want to verify your answer, just insert the value of v to the equation.

8 0
3 years ago
Find the de Broglie wavelength of the following. (a) a 4-MeV proton 14.3 Correct: Your answer is correct. fm (b) a 40-GeV electr
kherson [118]

a) de Broglie wavelength of a 4-MeV proton: 14.3 fm

b) de Broglie wavelength of a 40-GeV electron: 0.031 fm

Explanation:

a)

The de Broglie wavelength of an object is given by

\lambda=\frac{h}{p} (1)

where

h is the Planck constant

p is the momentum of the particle

Here we want to find the de Broglie wavelength of a 4-MeV proton. The rest of mass of the proton in MeV is

m_0 = 938 MeV

And since 4MeV, this means that the proton is non-relativistic. So its kinetic energy is related to its momentum by

E=\frac{p^2}{2m}

which means

p=\sqrt{2Em}

where

E=4 MeV \cdot 10^6 eV/MeV \cdot 1.6\cdot 10^{-19] J/eV=6.4\cdot 10^{-13} J is the kinetic energy

m=1.67\cdot 10^{-27} kg is the proton mass

Substituting, we find

\lambda=\frac{h}{\sqrt{2Em}}=\frac{6.63\cdot 10^{-34}}{\sqrt{2(6.4\cdot 10^{-13})(1.67\cdot 10^{-27})}}=14.3\cdot 10^{-15} m = 14.3 fm

b)

In this case, the electron has kinetic energy of 40 GeV, while the rest mass of an electron is

m_0 = 0.511 MeV

Since 40 GeV >> 0.511 MeV, the electron is ultra-relativistic: so we can rewrite its energy as

E = pc

The equation (1) can also be rewritten as

\lambda = \frac{hc}{pc}

where c is the speed of light. The quantity at the denominator is the energy, so

\lambda=\frac{hc}{E}

where:

E=40 GeV = 40\cdot 10^9 eV \cdot (1.6\cdot 10^{-19})=6.4\cdot 10^{-9} J is the energy of the electron

And substituting, we find:

\lambda=\frac{(6.63\cdot 10^{-34})(3\cdot 10^8)}{6.4\cdot 10^{-9}}=3.1 \cdot 10^{-17} m = 0.031 fm

Learn more about de Broglie wavelength:

brainly.com/question/7047430

#LearnwithBrainly

4 0
3 years ago
Determine the force of gravity on a 1600 kg spaceship: near the surface of the Moon.
Umnica [9.8K]

Answer:

yahoo has the answer im telling you

Explanation:

3 0
3 years ago
a block with a mass of 3 kg is swung on a cord in a horizontal circle with a radius of 2m. the speed of the block is 6m/s^. the
Ivenika [448]

Given Information:  

Mass = m = 3 kg

Speed = v = 6 m/s  

Radius = r = 2 m

Required Information:  

Magnitude of the acceleration = a = ?  

Answer:

Magnitude of the acceleration = 18 m/s²

Explanation:

The acceleration of the block traveling along a circular path with some velocity is given by

a = v²/r

a = 6²/2

a = 36/2

a = 18 m/s²

Therefore, the magnitude of the acceleration of the block is most nearly equal to 18 m/s².

Bonus:

The corresponding force acting on the block can be found using

F = ma (a = v²/r)

F = mv²/r

7 0
3 years ago
Read 2 more answers
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