Question

The voltage across a membrane forming a cell wall is 72.7 mV and the membrane is 9.22 nm thick. What is the magnitude of the electric field strength? (The value is surprisingly large, but correct.) You may assume a uniform E-field.

Answer 1

Answer:

The  magnitude of the  electric field intensity is  $E = 7.89 *10^{6} \ V/m$

Explanation:

From the question we are told that

    The  voltage is  $\epsilon = 72.7 \ mV = 72.7 *10^{-3} V$

    The  thickness of the membrane is  $t = 9.22 \ nm = 9.22 *10^{-9} \ m$

     

Generally the electric field intensity is mathematically represented as

                $E = \frac{\epsilon }{t}$

 substituting values

                $E = \frac{72.7 *10^{-3} }{9.22 *10^{-9}}$

                $E = 7.89 *10^{6} \ V/m$