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a_sh-v [17]
3 years ago
7

A student releases a marble from the top of a ramp. The marble increases speed while on the ramp then continues across the floor

. The marble travels a total of 120cm in 3.40s.
What is the final velocity (in cm/s)
Physics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

35.2941176 cm/s

Explanation:

round it if you need too

Distance divided by time.

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Explanation:

It is given that,

Mass of the ball, m = 0.06 kg

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(a) Let J is the magnitude of the impulse delivered to the ball by the racket. It can be calculated as the change in momentum as :

J=m(v-u)

J=0.06\times (-37-(50.4))  

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(b) Let W is the work done by the racket on the ball. It can be calculated as the change in kinetic energy of the object.

W=\dfrac{1}{2}m(v^2-u^2)

W=\dfrac{1}{2}\times 0.06\times ((-37)^2-(50.4)^2)

W = -35.1348 Joules

Hence, this is the required solution.

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