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a_sh-v [17]
3 years ago
7

A student releases a marble from the top of a ramp. The marble increases speed while on the ramp then continues across the floor

. The marble travels a total of 120cm in 3.40s.
What is the final velocity (in cm/s)
Physics
1 answer:
Sergeu [11.5K]3 years ago
7 0

Answer:

35.2941176 cm/s

Explanation:

round it if you need too

Distance divided by time.

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Al is floating freely in her spacecraft, and you are accelerating away from her with an acceleration of 1g. 5) How will you feel
wariber [46]

Answer:

D. You will feel the same weight as you do on Earth

Explanation:

In free space, she is suppose to be weightless.

Free fall can be described as body in motion where the body is under the effect of acceleration due to gravity only and no other acceleration..

Since I am accelerating away from her at an acceleration of 1g

Then,

F=ma, where a=g

Then F=mg

Since my weight on earth is W=mg

This is equals to my weight in the spaceship, then I will feel the same weights as I do on earth.

5 0
3 years ago
Scientific models have two basic types. Please select the best answer from the choices provided T F
Ede4ka [16]

Answer:

Scientific models have two basic types. FALSE.

Hoped I helped

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3 years ago
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How to calculate the average value of the indirect measurements of KE
Tom [10]

Answer:

1/2 m*(2(h)/t)*g

Explanation:

8 0
3 years ago
A resistor is connected in series with a power supply of 23.90 V. The current measure is 0.60 A. What is the resistance (in Ω) o
Yuliya22 [10]

The resistance in this circuit is 39.8 ohms.

Explanation:

Any circuit having resistor, battery and ammeter connected in series will obey the ohm's law in basic case. So according to the Ohm's law, the current flowing in the circuit through the ammeter will be equal to the voltage shown in the voltmeter or battery and resistor is the proportionality constant. So with this law

V = IR

So, Resistance R = V/I

As the voltage is given as 23.90 V and the current is given as 0.6 A, then resistance is

R = 23.90/0.6 = 39.8 ohms.

So, the resistance in this circuit is 39.8 ohms.

8 0
3 years ago
For a huge luxury liner to move with constant velocity, its engines need to supply a forward thrust of 6.85 105 N. What is the m
Leviafan [203]

Answer:

The magnitude of the resistive force exerted by the water is 6.85\times 10^{5} newtons.

Explanation:

By First and Second Newton's Law, the resistive force exerted by the water on the cruise ship has the same magnitude of forward thrust, with which it is antiparallel to. The equation of equilibrium for the luxury liner is:

\Sigma F = F-R = 0 (Eq. 1)

Where:

F - Forward trust, measured in newtons.

R - Resistive force exerted by the water, measured in newtons.

From (Eq. 1), we get that: (F = 6.85\times 10^{5}\,N)

R = F

R = 6.85\times 10^{5}\,N

The magnitude of the resistive force exerted by the water is 6.85\times 10^{5} newtons.

4 0
3 years ago
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