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Olegator [25]
3 years ago
7

Where in the circuit of (Figure 1) is the current the largest, (a), (b), (c), or (d)?

Physics
1 answer:
strojnjashka [21]3 years ago
6 0
"<span>The current is the same at all points" is the one among the following choices given in the question that answers the question correctly. The correct option among all the options that are given in the question is the fifth option or the last option. I hope that this is the answer that has come to your desired help.</span>
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The sun is made up mostly of
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Answer:

the first one, gas

Explanation:

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The main light gathering device of a refractor telescope is
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It's the "objective" lens ... the big one in the front.

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A tradesman sharpens a knife by pushing it with a constant force against the rim of a grindstone. The 30-cm-diameter stone is sp
Lorico [155]

Answer:

a. 0.21 rad/s2

b. 2.205 N

Explanation:

We convert from rpm to rad/s knowing that each revolution has 2π radians and each minute is 60 seconds

200 rpm = 200 * 2π / 60 = 21 rad/s

180 rpm = 180 * 2π / 60 = 18.85 rad/s

r = d/2 = 30cm / 2 = 15 cm = 0.15 m

a)So if the angular speed decreases steadily (at a constant rate) from 21 rad/s to 18.85 rad/s within 10s then the angular acceleration is

\alpha = \frac{\Delta \omega}{\Delta t} = \frac{21 - 18.85}{10} = 0.21 rad/s^2

b) Assume the grind stone is a solid disk, its moment of inertia is

I = mR^2/2

Where m = 28 kg is the disk mass and R = 0.15 m is the radius of the disk.

I = 28*0.15^2/2 = 0.315 kgm^2

So the friction torque is

T_f = I\alpha = 0.315*0.21 = 0.06615 Nm

The friction force is

F_f = T_f/R = 0.06615 / 0.15 = 0.441 N

Since the friction coefficient is 0.2, we can calculate the normal force that is used to press the knife against the stone

N = F_f/\mu = 0.441/0.2 = 2.205 N

7 0
3 years ago
A rocket has landed on Planet X, which has half the radius of Earth. An astronaut onboard the rocket weighs twice as much on Pla
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Explanation:

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g_X=GM/R^2

Here,g_X = 2g

Escape velocity is given by:

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Here, R=R_earth/2

and g_X = 2g

Therefore,v=\sqrt(2(2g)(R/2))=v_0

7 0
3 years ago
Can y’all help me on number 2
Temka [501]

Answer:

sure

Explanation:

7 0
3 years ago
Read 2 more answers
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