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abruzzese [7]
3 years ago
5

Why isn't the story of Israel not fully accurate?

Physics
2 answers:
Setler [38]3 years ago
8 0

Answer:

the story of Israel is part of the Bible that's what what you're your lesson is

Explanation:

maksim [4K]3 years ago
5 0

Answer:

wait what do you mean? And why is this in physics?

Is this about the iron dome or something biblical?

Explanation:

You might be interested in
Can someone please answer this, ill give you brainliest Would be very appreciated.
Whitepunk [10]

Answer:

frost wedging

Explanation:

When glaciers melt and the rock beneath is weathered and broken down, this is called frost wedging.

6 0
2 years ago
+
Triss [41]

The acceleration of the boat is 2 m/s^2 (eastward)

Explanation:

We can solve this problem by using Newton's second law, which states that:

F = ma (1)

where

F is the net force on a body

m is its mass

a is its acceleration

First of all, we have to find the net force acting on the boat. We have:

- The force of the motor, 100 N eastward

- The force of the air resistance, 60 N westward

So the net force is:

F = 100 N - 60 N = 40 N (eastward)

Now we can apply eq.(1), using:

F = 40 N

m = 20 kg (mass of the boat)

and solving for a, we find the acceleration:

a=\frac{F}{m}=\frac{40}{20}=2.0 m/s^2

And the direction is the same as the net force (eastward).

Learn more about acceleration and Newton laws of motion:

brainly.com/question/11411375

brainly.com/question/1971321

brainly.com/question/2286502

brainly.com/question/2562700

#LearnwithBrainly

4 0
3 years ago
A projectile thrown from the ground reached a horizontal displacement of 50 [m] and a maximum height of 100 [m]. What are the ma
Semenov [28]

Answer:

\theta=82.87^0

u = 44.44 m/s

Explanation:

given,

horizontal displacement = 50 m

maximum height = 100 m

initial velocity (v₀) = ?

launching angle(θ) = ?

using formula

R = \dfrac{u^2sin2\theta}{g}........(1)

h = \dfrac{u^2sin\theta}{2g}.........(2)

dividing equation (2)/(1)

\dfrac{h}{R} = \dfrac{\dfrac{u^2sin\theta}{2g}}{\dfrac{u^2sin2\theta}{g}}

\dfrac{h}{R} =\dfrac{sin^2\theta}{2sin2\theta}

\dfrac{4h}{R} =tan \theta

\theta= tan{-1}{\dfrac{4\times 100}{50}}

\theta=82.87^0

now using equation (2)

100 = \dfrac{u^2sin82.87^0}{2\times 9.81}

u = 44.44 m/s

5 0
3 years ago
A test rocket is launched vertically from ground level (y = 0 m), at time t = 0.0 s. The rocket engine provides constant upward
SVETLANKA909090 [29]
The important thing to note here is the direction of motion of the test rocket. Since it mentions that the rocket travels vertically upwards, then this motion can be applied to rectilinear equations that are derived from Newton's Laws of Motions.These useful equations are:

y = v₁t + 1/2 at²
a = (v₂-v₁)/t

where
y is the vertical distance travelled
v₁ is the initial velocity
v₂ is the final velocity
t is the time 
a is the acceleration

When a test rocket is launched, there is an initial velocity in order to launch it to the sky. However, it would gradually reach terminal velocity in the solar system. At this point, the final velocity is equal to 0. So, v₂ = 0. Let's solve the second equation first.

a = (v₂-v₁)/t
a = (0-30)/t
a = -30/t

Let's substitute a to the first equation:
y = v₁t + 1/2 at²
49 = 30t + 1/2 (-30/t)t²
49 = 30t -15t
49 = 15 t
t = 49/15
t = 3.27 seconds

3 0
3 years ago
How to find wavelength
Andrews [41]
If the wavelength<span> is given, the energy can be determined by first using the wave equation (c = λ × ν) to </span>find<span> the frequency, then using Planck's equation to </span>calculate<span> energy. Use the equations above to answer the following questions. 1. Ultraviolet radiation has a frequency of 6.8 × 1015 1/s.</span>
4 0
3 years ago
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