Answer:
change in entropy is 1.44 kJ/ K
Explanation:
from steam tables
At 150 kPa
specific volume
Vf = 0.001053 m^3/kg
vg = 1.1594 m^3/kg
specific entropy values are
Sf = 1.4337 kJ/kg K
Sfg = 5.789 kJ/kg
initial specific volume is calculated as





FROM STEAM Table
at 200 kPa
specific volume
Vf = 0.001061 m^3/kg
vg = 0.88578 m^3/kg
specific entropy values are
Sf = 1.5302 kJ/kg K
Sfg = 5.5698 kJ/kg
constant volume so




Change in entropy 
=3( 3.36035 - 2.88) = 1.44 kJ/kg
Answer:
(a) x0 = 0m and y0 = 49.0m
(b) Vox = 15.0m/s Voy = 0m/s
(c) Vx = Vo = 15.0m/s and Vy = -gt
(d) X = 15.0t and y = 49.0 - 4.9t²
(e) t = 3.16s
(f) Vf = 34.4m/s
Explanation:
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<h3>Answer</h3>
a. 8J
b. 90J
<h3>Notes formula</h3>
W = F × s
W = Work done (J)
F = Force (N)
s = distance (m)
<h3>Known that </h3>
a. F = 4N
s = 2m
b. F = 30N
s = 3m
<h3>Question</h3>
a. W = ..?
b. W = ..?
<h3>Way to do it</h3>
a. W = F × s
= 4N × 2m = 8J
b. W = F × s
= 30N × 3m = 90J
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