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STatiana [176]
3 years ago
8

The chemical's name to the right, in molecular or ionic compound , usually ends in -ide How do we know which chemical goes first

when we are naming covalent compounds ?
Physics
1 answer:
Katen [24]3 years ago
7 0

Answer:

The name of the highly Electropositive element goes first.

e.g

Cl_{2}O \:  =  >  \: dichloride \: oxide

Chlorine is more Electropositive than Oxygen.

e.g

NO_{2} \:  =  >  \: nitrogen \: dioxide

Nitrogen is more Electropositive than Oxygen

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Physics approach to study macromoelcues at nanoscales <br> in detail plx
erastova [34]

Answer:

Abstracto

Los ácidos nucleicos y las proteínas comprenden una red de biomacromoléculas que almacenan y transmiten información que sustenta la vida de la célula. El estudio de estos mecanismos es un campo llamado biología molecular. El desarrollo de esta ciencia siempre ha ido acompañado de avances técnicos que permiten romper barreras metodológicas para probar hipótesis novedosas. Entre los métodos disponibles para los biólogos moleculares, destacan cinco: electroforesis, secuenciación, clonación, transferencia y reacción en cadena de la polimerasa. Su impacto llega a la genética, la medicina y la biotecnología. Aquí, se revisan la relevancia histórica, los fundamentos técnicos y las tendencias actuales de estos cinco métodos esenciales. La revisión pretende ser útil tanto para estudiantes como para científicos profesionales que buscan adquirir conocimientos avanzados sobre el valor de estos métodos para investigar los mecanismos moleculares que sostienen la vida.

8 0
3 years ago
A copper wire of resistivity 2.6 × 10-8 Ω m, has a cross sectional area of 35 × 10-4 cm2
KengaRu [80]

Answer:

the length of the wire is 134.62 m.

Explanation:

Given;

resistivity of the copper wire, ρ = 2.6 x 10⁻⁸ Ωm

cross-sectional area of the wire, A  = 35 x 10⁻⁴ cm² = ( 35 x 10⁻⁴) x 10⁻⁴ m²

resistance of the wire, R = 10Ω

The length of the wire is calculated as follows;

R = \frac{\rho L}{A} \\\\L = \frac{RA}{\rho} \\\\L= \frac{10 \times (35\times 10^{-4}) \times 10^{-4}}{2.6 \times 10^{-8}} \\\\L = 134.62 \ m

Therefore, the length of the wire is 134.62 m.

6 0
3 years ago
A golf ball strikes a hard, smooth floor at an angle of 28.2 ° and, as the drawing shows, rebounds at the same angle. The mass o
WITCHER [35]

Answer:

    I = 1.06886  N s

Explanation:

The expression for momentum is

          I = F t = Δp

therefore the momentum is a vector quantity, for which we define a reference system parallel to the floor

Let's find the components of the initial velocity

          sin 28.2 = v_y / v

          cos 28.2=  vₓ / v

          v_y = v sin 282

          vₓ = v cos 28.2

          v_y = 42.8 sin 28.2 = 20.225 m / s

          vₓ = 42.8 cos 28.2 = 37.72 m / s

since the ball is heading to the ground, the vertical velocity is negative and the horizontal velocity is positive, it can also be calculated by making

θ = -28.2

         v_y = -20.55 m / s

         v_x = 37.72 m / s

X axis

         Iₓ = Δpₓ = p_{fx} - p_{ox}

since the ball moves in the x-axis without changing the velocity, the change in moment must be zero

         Δpₓ = m v_{fx} - m v₀ₓ = 0

          v_{fx} = v₀ₓ

therefore

          Iₓ = 0

Y axis  

        I_y = Δp_y = p_{fy} -p_{oy}

when the ball reaches the floor its vertical speed is downwards and when it leaves the floor its speed has the same modulus but the direction is upwards

         v_{fy} = - v_{oy}

         Δp_y = 2 m v_{oy}

         Δp_y = 2 0.0260 (20.55)

         \Delta p_{y} = 1.0686 N s

the total impulse is

          I = Iₓ i ^ + I_y j ^

          I = 1.06886  j^ N s

7 0
3 years ago
true or false refraction occurs when the amplitude of a wave changes as it goes from one medium to aother​
KiRa [710]

The answer here is true

4 0
3 years ago
At an outdoor market, a bunch of bananas is set into oscillatory motion with an amplitude of 34.7998 cm on a spring with a sprin
Otrada [13]

Answer:

W = 32.03316 N

Explanation:

given,

Amplitude, A = 34.7998 cm = 0.347998 m

spring constant, k = 13.5666 N/m

maximum speed, v = 70.8966 cm/s = 0.708966 m/s

acceleration due to gravity, g = 9.8 m/s²

weight of the banana = ?

using maximum speed formula

v_{max} = A \sqrt{\dfrac{k}{m}}

squaring both side

v_{max}^2 = A^2 \dfrac{k}{m}

m = \dfrac{A^2k}{v_{max}^2}

m = \dfrac{0.347998^2\times 13.5666}{0.708966^2}

  m = 3.26868 Kg

weight

W = mg

W= 3.26868 x 9.8

W = 32.03316 N

hence, weight of Banana is equal to W = 32.03316 N

7 0
3 years ago
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