The exosphere is the layer of the atmosphere "Where gas molecules can be exchanged between Earth's atmosphere and outer space." Thus, the answer would be C.
Answer:
10 kg
Explanation:
The mass of an object does not change even if the amount of gravtiy changes.
I think trace 1 is ac and trace 2 if dc but i’m not sure what will happen when a higher frequency is added?
Answer:
16.45 m/s
Explanation:
Let y be the vertical distance and x be the horizontal distance
We are given that
The altitude of hang glider increasing at the rate=![v_y=\frac{dy}{dt}==6.75m/s](https://tex.z-dn.net/?f=v_y%3D%5Cfrac%7Bdy%7D%7Bdt%7D%3D%3D6.75m%2Fs)
The shadow of the glider moves along the ground at speed=![v_x=\frac{dx}{dt}=15m/s](https://tex.z-dn.net/?f=v_x%3D%5Cfrac%7Bdx%7D%7Bdt%7D%3D15m%2Fs)
We have to find the magnitude of glider's velocity.
We know that
Magnitude of velocity=![v=\sqrt{v^2_x+v^2_y}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bv%5E2_x%2Bv%5E2_y%7D)
Substitute the values
![v=\sqrt{(15)^2+(6.75)^2}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B%2815%29%5E2%2B%286.75%29%5E2%7D)
![v=\sqrt{225+45.5625}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B225%2B45.5625%7D)
![v=16.45m/s](https://tex.z-dn.net/?f=v%3D16.45m%2Fs)
Hence, the magnitude of glider's velocity=16.45 m/s