The change of velocity is from 18.5 to 46.1 m/s or 46.1 - 18.5 = 27.6 m/s. The time of change is 2.47 s. So the acceleration is 27.6 m/s / 2.47 s = 11.17 m/s^2. The distance traveled is average velocity times time of travel.
Answer: A car slows from 22 m/s to 3.0 m/s at a constant rate of 2.1 m/s2. How many seconds are required before the car is a r2.1 m/s2 traveling at 3.0 m/s?
5 pages
Explanation:
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Answer:
A= Q/4 B=0 C=Q/4
Explanation:
The initial condition, is as follows:
A=Q B=0 C=0
When A is brought to contact with B, as both spheres are conductors, charge distribute evenly between the two spheres, so after this, the charges on the spheres are as follows:
A= Q/2 B=Q/2 C=0
If B touches C, while C is grounded, this supplies a infinite source of sink of charge, so both spheres lose any charge.
At this stage, the charge distribution is as follows:
A = Q/2 B=0 C=0
Assuming C is not grounded, when finally touches A, the charge on A distributes evenly between A and C, so the final situation is as follows:
A = Q/4 B=0 C=Q/4
Isaac Newton<span>The three laws of motion were first compiled by Isaac Newton in his Philosophiæ Naturalis Principia Mathematica (Mathematical Principles of Natural Philosophy), first published in 1687. Newtonused them to explain and investigate the motion of many physical objects and systems.</span>