Explanation:
It is given that, the field near a typical pulsed-field machine rises from 0 T to 2.5 T in 200 μs
Change in magnetic field, 
Change in time, 
Diameter, d = 2.3 cm
Radius, r = 0.0115 m
Emf is induced in the ring as the field changes. It is given by :




E = 5.19 volts
So, the emf induced in the ring is 5.19 volts. Hence, this is the required solution.
It's gotta be purple!!!!!!!!!!!!!!!
The force (expressed in N), the egg experience upon hitting the ground is 3.5N.
<h3>What is Net force?</h3>
When two or more forces are acting on the system of objects, then the to attain equilibrium, net force must be zero.
Given is an 0.07 kg egg and toss if from a window 30 m above the ground. The egg reaches and maintains a falling speed of 0.5 m/sec. Upon reaching the ground, the egg rapidly decelerates to 0 m/sec over the course of only 0.01 seconds.
<h3>Average force = Mass x acceleration</h3>
F = m x (Vf -Vi)/t
F = 0.07 x (0 - 0.5)/0.01
F = -3.5N
Thus, the magnitude of force on egg upon hitting the ground is 3.5N.
Learn more about net force.
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Answer:
613373.65233 m/s
Explanation:
M = Mass of Sun = 
m = Mass of Earth
v = Velocity of Earth
r = Distance between Earth and Sun = 
= Radius of Earth = 
= Radius of Sun = 
In this system it is assumed that the potential and kinetic energies are conserved

The velocity of Earth would be 613373.65233 m/s