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3 years ago

If you run a 500 W computer for 4 hours, your electric meter will read ; this is a measure of ___ "used"

Physics

2 answers:

emmasim [6.3K]3 years ago

7 0

Answer:

If you run a 500 W computer for 4 hours, your electric meter will read 2kWh; this is a measure of energy "used". The correct answer is D.

Explanation: Energy is defined as the capacity of doing work and is occurs in different forms( electrical, kinetic, potential energy). Electrical energy consumption can be calculated or measure through the multiplication of the power( W or kW) used by the number of hours during which the power is consumed. Therefore the unit of energy is kWh. From the question,

500W was used for 4 H

Therefore energy consumed

500× 4= 2000Wh. To convert to kWh

Divide by 1000,

2000÷ 1000= 2.

There energy consumed in kWh is,

2kWh energy.

Katen [24]3 years ago

3 0

Answer:

D) 2 kWh, energy

Explanation:

Energy = power×time

For electricity,

E = Pt.................... Equation 1

Where E = Electric Energy, P = power, t = time.

Given: P = 500 W, t = 4 hours.

Substitute into equation 1

E = 500(4)

E = 2000 Wh

E = (2000/1000) kWh

E = 2 kWh.

Hence the right option is D) 2 kWh, energy

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Answer:

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3 years ago

Which of these is the most ductile? A. clay B. gold C. wood D. glass

Feliz [49]

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3 years ago

A 13561 N car traveling at 51.1 km/h rounds

Minchanka [31]

Answer:

a) The centripetal acceleration of the car is 0.68 m/s²

b) The force that maintains circular motion is 940.03 N.

c) The minimum coefficient of static friction between the tires and the road is 0.069.

Explanation:

a) The centripetal acceleration of the car can be found using the following equation:

$a_{c} = \frac{v^{2}}{r}$

Where:

v: is the velocity of the car = 51.1 km/h

r: is the radius = 2.95x10² m

$a_{c} = \frac{(51.1 \frac{km}{h}*\frac{1000 m}{1 km}*\frac{1 h}{3600 s})^{2}}{2.95 \cdot 10^{2} m} = 0.68 m/s^{2}$

Hence, the centripetal acceleration of the car is 0.68 m/s².

b) The force that maintains circular motion is the centripetal force:

$F_{c} = ma_{c}$

Where:

m: is the mass of the car

The mass is given by:

$P = m*g$

Where P is the weight of the car = 13561 N

$m = \frac{P}{g} = \frac{13561 N}{9.81 m/s^{2}} = 1382.4 kg$

Now, the centripetal force is:

$F_{c} = ma_{c} = 1382.4 kg*0.68 m/s^{2} = 940.03 N$

Then, the force that maintains circular motion is 940.03 N.

c) Since the centripetal force is equal to the coefficient of static friction, this can be calculated as follows:

$F_{c} = F_{\mu}$

$F_{c} = \mu N = \mu P$

$\mu = \frac{F_{c}}{P} = \frac{940.03 N}{13561 N} = 0.069$

Therefore, the minimum coefficient of static friction between the tires and the road is 0.069.

I hope it helps you!

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2 years ago

If you run a 500 W computer for 4 hours, your electric meter will read ____; this is a measure of _______ "used"

If you run a 500 W computer for 4 hours, your electric meter will read ; this is a measure of ___ "used"