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3 years ago

An object has a positive velocity to the right and a negative acceleration. what is the motion of the object?

1 answer:

5 0

The object's motion toward the right is slowing down ... the magnitude of his velocity is decreasing. If this goes on long enough, his velocity will dwindle to zero, and then become negative ... he'll start moving to the left.

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Five metal samples, with equal masses, are heated to 200oC. Each solid is dropped into a beaker containing 200 ml 15oC water. Wh

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<span>B) copper is the answer shoot im late </span>

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4 years ago

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In this image of a pendulum, where is the lowest potential energy found?

uranmaximum [27]

Think about the formula for potential energy. (Surely you remember it):

Potential energy = (mass) x (acceleration of gravity) x (height)

-- The mass on the end of the pendulum doesn't change.

-- The acceleration of gravity doesn't change.

-- The only thing that changes is the height of the mass on the end.

So the potential energy is lowest when its height is the lowest.

That's position <em>B </em>.

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3 years ago

Most of the mass of the milky way exists in the form of.

Andrews [41]

Answer: Dark matter.

Explanation: Hope it helps :)

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3 years ago

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A wagon is rolling forward on level ground. Friction is negligible. The person sitting in the wagon is holding a rock. The total

Rudik [331]

Answer:

a) 0.41 m/s

b) 0.51 m/s

Explanation:

(a)

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (15.4) + (93.1 - 0.292) V'

V' = 0.41 m/s

M = total mass of wagon, rider and the rock = 93.1 kg

V = initial velocity of wagon = 0.456 m/s

m = mass of the rock = 0.292 kg

v = velocity of rock after throw = - 15.4 m/s

V' = velocity of wagon after rock is thrown

Using conservation of momentum

M V = m v + (M - m) V'

(93.1) (0.456) = (0.292) (- 15.4) + (93.1 - 0.292) V'

V' = 0.51 m/s

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4 years ago

Bonus Points. A ball was thrown straight up in the air from 1.2 meter above the grouind. After 3 seconds the ball returnes to th

nekit [7.7K]

Answer:

Explanation:

given that

Distance above the ground, s = 1.2 m

Time taken by the ball, t = 3 s

Velocity of the ball, v = 1.2/3 = 0.4 m/s

Maximum height reached by the ball is then given by the formula

H = v² / 2g

H = 0.4² / 2 * 9.8

H = 0.16 / 19.6

H = 0.0082 m or rather, 0.82 cm

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3 years ago