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Inga [223]
3 years ago
5

If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the cu

rve (a real problem on icy mountain roads). (a) Calculate the minimum speed, in meters per second, required to take a 84 m radius curve banked at 16° so that you don't slide inwards, assuming there is no friction. (b) What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 16 km/h?

Physics
2 answers:
kvasek [131]3 years ago
7 0

Answer:

Please see attachment

Explanation:

Please see attachment

zubka84 [21]3 years ago
4 0

Answer:

minimum speed is 15.35 m/s

frictional coefficient  is 0.26

Explanation:

given data

radius = 84 m

angle = 16°

speed = 16 km/h = 4.43 m/s

to find out

minimum speed and   minimum coefficient

solution

we will apply here formula for velocity that is

velocity² = radius × g × tanθ

v² = 84 × 9.8 × tan16

v² =  236.04

v = 15.35 m/s

and

we find first friction force here

friction force 1 = m v² /r

friction force 1 = m (15.35)² / 84 = 2.80 m

and

friction force 2 = m v² /r

friction force 2 = m (4.43)² / 84 =  0.245 m

so total friction force = f1 - f2

total friction force = 2.80 - 0.245  = 2.55 m

so frictional coefficient = friction force /g

frictional coefficient = 2.55 / 9.8

so frictional coefficient  is 0.26

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Korolek [52]

Answer:

Potential Energy = 294J, Kinetic Engergy = 48.02J

Explanation:

We have these formulas:

Potential Energy = mass * gravitational force * height (m) = 1 * 9.8 * 30 = 294(J)

Kinetic Energy = 1/2 * mass * velocity^2 = 1/2 * 1 * 9.8^2 = 48.02 (J)

As the rock falling at an acceleration of 9.8m/s^2 which means for each second, the rock increases 9.8m/s. I think we are missing time to find the instantaneous velocity, the formula is (initial displacement - final displacement)/ (initial time - final time) which will directly give the final answer for you.

 

5 0
4 years ago
- With the device starting from a still position (0 m/s), you drop it, allowing gravity to accelerate it towards the ground at 9
IrinaVladis [17]
Starting velocity (u)=0
acceleration (a) = 9.8
time (t) = 1.5
final velocity (v) =?

v=at+u
v=9.8(1.5)+0
v=14.7m/s2
3 0
3 years ago
To determine the coefficient of static friction between two materials, an engineer places a small sample of one material on a ho
Fudgin [204]

This question is incomplete, the missing image is uploaded along this answer.

Answer:

the coefficient of friction is 0.32

Explanation:

 Given the data in the question;

we make use of kinematic equation of motion;

ω = ω₀ + ∝t

we substitute

ω = ( 0 rad/s ) + ( 0.4 rad/s² )( 9.903 s )

ω = 3.9612 rad/s

The centripetal force acting on the sample is;

Fc = mrω²

from the image; r = 200 mm = 0.2 m

so we substitute

Fc = m(0.2 m ) ( 3.9612 rad/s )²

Fc = (3.13822 m/s²)m

we know that the frictional force between the two materials should be providing the necessary centripetal force to rotate the sample object;

f = Fc

μN = Fc

μmg = (3.13822 m/s²)m

μ = (3.13822 m/s²)m / mg

μ = (3.13822 m/s²) / g

acceleration due to gravity g = 9.8 m/s²

so

μ = (3.13822 m/s²) / 9.8 m/s²

μ = 0.32

Therefore, the coefficient of friction is 0.32

5 0
3 years ago
Find the velocity of a dropped brick after 5.0 s using v =a ∆ t and a = - 9.8 m/s^2
Verizon [17]

Answer:

49

Explanation:

9.8 x 5 = 49

8 0
3 years ago
How would you measure the potential difference across a resistor?
coldgirl [10]
You would need to connect a potential difference across a resistor in parallel
8 0
3 years ago
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