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3 years ago

PLEASE I NEED ANSWER ASAP

Mathematics

1 answer:

mafiozo [28]3 years ago

8 0

Answer:

42°

Step-by-step explanation:

$(7x - 2) \degree = (6x + 18) \degree\\ ..(exterior \: alternate \: \angle s) \\ 7x - 2 = 6x + 18 \\ 7x - 6x = 18 + 2 \\ x = 20 \\ \\ (7x - 2) \degree + \angle \: 1 = 180 \degree \\..(straight \: line \: \angle s) \\ (7 \times 20 - 2) \degree+ \angle \: 1 = 180 \degree \\ 138 \degree+ \angle \: 1 = 180 \degree \\ \angle \: 1 = 180 \degree - 138 \degree \\ \angle \: 1 = 42\degree$

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beks73 [17]

Answer:

Below.

Step-by-step explanation:

Plot following points.

Calculate the point by plugging in values of x into x^2 + 1

for example When x = 0, y = 0^1 + 1 = 1.

So plot plot (0, 1),

Make a table of points to plot:

x -3 -2 -1 0 1 2 3

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When you plot the points you'll see the graph is U shaped.

The function is of second degree (as it contains x^2) so it wont be linear.

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3 years ago

Examine the fraction 3+2i4−2i. Which expression is the first step to simplify the fraction? 3+2i4−2i⋅3−2i3−2i

umka2103 [35]

Answer:

The correct answer is the last option.

Step-by-step explanation:

When you have a fraction with complex numbers, the first step to simplify is to multiply up and down the conjugate of the denominator, this will eliminate the complex part of the denominator, and in this way you can separate the expression in its real and complex part.

For the expression:

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The denominator conjugate is 4 + 2i

When multiplied, the denominator is:

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3 years ago

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IRISSAK [1]

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Step-by-step explanation:

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3 years ago

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Suppose that a cyclist began a 476

mojhsa [17]

Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus $\bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}$

solve for "r", to see how fast the cyclist was going

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3 years ago

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OLga [1]

Answer:

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