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FrozenT [24]
3 years ago
11

PLEASE I NEED ANSWER ASAP

Mathematics
1 answer:
mafiozo [28]3 years ago
8 0

Answer:

42°

Step-by-step explanation:

(7x - 2) \degree = (6x + 18) \degree\\ ..(exterior \: alternate \:  \angle s) \\ 7x - 2 = 6x + 18 \\ 7x - 6x = 18 + 2 \\ x = 20 \\  \\ (7x - 2) \degree +  \angle \: 1 = 180 \degree \\..(straight \: line \:  \angle s) \\ (7 \times 20 - 2) \degree+  \angle \: 1 = 180 \degree  \\ 138 \degree+  \angle \: 1 = 180 \degree  \\  \angle \: 1 = 180 \degree - 138 \degree \\  \angle \: 1 = 42\degree

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Find several points that are on the graph of the function y = x^2 + 1. Plot the points in a coordinate plane.
beks73 [17]

Answer:

Below.

Step-by-step explanation:

Plot following points.

Calculate the point by plugging in values of x into x^2 + 1

for example When x = 0, y = 0^1 + 1 = 1.

So plot plot (0, 1),

Make a table of points to plot:

x   -3    -2    -1    0    1    2     3

y   10     5     2   1     2   5    10

When you plot the points you'll see the graph is U shaped.

The function is of second degree (as it contains x^2) so it wont be linear.

8 0
3 years ago
Examine the fraction 3+2i4−2i. Which expression is the first step to simplify the fraction? 3+2i4−2i⋅3−2i3−2i
umka2103 [35]

Answer:

The correct answer is the last option.

Step-by-step explanation:

When you have a fraction with complex numbers, the first step to simplify is to multiply up and down the conjugate of the denominator, this will eliminate the complex part of the denominator, and in this way you can separate the expression in its real and complex part.

For the expression:

\frac{3 + 2i}{4-2i
}

The denominator conjugate is 4 + 2i

When multiplied, the denominator is:

4 ^ 2 -4i ^ 2 = 16 -4 (-1) = 20

4 0
3 years ago
X y
IRISSAK [1]

Answer: let me check

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Suppose that a cyclist began a 476
mojhsa [17]
Well, we know the cyclist left the western part going eastwards, at the same time the car left the eastern part going westwards

the distance between them is 476 miles, and they met 8.5hrs later

let's say after 8.5hrs, the cyclist has travelled "d" miles, whilst the car has travelled the slack, or 476-d, in the same 8.5hrs

we know the rate of the car is faster... so if the cyclist rate is say "r", then the car's rate is r+33.2

thus    \bf \begin{array}{lccclll}
&distance&rate&time\\
&-----&-----&-----\\
\textit{eastbound cyclist}&d&r&8.5\\
\textit{westbound car}&476-d&r+33.2&8.5
\end{array}\\\\
-----------------------------\\\\
\begin{cases}
\boxed{d}=8.5r\\\\
476-d=(r+33.2)8.5\\
----------\\
476-\boxed{8.5r}=(r+33.2)8.5
\end{cases}

solve for "r", to see how fast the cyclist was going

what about the car? well, the car's rate is r + 33.2
6 0
3 years ago
If on a scale drawing 24 inches equals 10 ft. what does 1/8 inches equal
OLga [1]

Answer:

 \large\boxed{\large\boxed{(5/96)ft\approx 0.052ft}}

Explanation:

1. Use the scale ratio to set a proportion with the unknown lenght.

       24inches/10ft=(1/8)inches/x

2. To solve for x, use cross multiplication:

        24inches\times x=10ft\times(1/8)inches

3. Divide both sides by 24inches:

          x=10ft\times(1/8)inches\times (1/24inches)

4. Simplify:

          x=10ft/192=(5/96)ft\approx 0.052ft

6 0
3 years ago
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