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nata0808 [166]
3 years ago
8

The standard configuration for an Arizona license plate is 3 digits (0 - 9) followed by 3 letters (of 26). If you can not repeat

digits or letters, how many plates (NO COMMAS NEEDED) can be made?
Mathematics
1 answer:
Anna71 [15]3 years ago
5 0

Answer:

11232000 plates can be made.

Step-by-step explanation:

The order of the digits and of the letters is important. For example, ABC is a different configuration than CBA. So we use the permutations formula to solve this question.

Permutations formula:

The number of possible permutations of x elements from a set of n elements is given by the following formula:

P_{(n,x)} = \frac{n!}{(n-x)!}

In this question:

3 digits from a set of 10(there are 10 digits from 0 to 9).

3 letters from a set of 26. So

Total:

T = P_{(10,3)} \times P_{(26,3)} = \frac{10!}{(10-3)!} \times \frac{26!}{(26-3)!} = 11232000

11232000 plates can be made.

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To study the output of a machine that fills boxes with cereal, a quality control engineer weighed 150 boxes of Brand X cereal. T
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\sigma = 0.07770

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Given

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Required

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x_1 = \frac{1}{2}(15.3 + 15.6) =\frac{1}{2} * 30.9 = 15.45

x_2 = \frac{1}{2}(15.6 + 15.9) =\frac{1}{2} * 31.5 = 15.75

x_3 = \frac{1}{2}(15.9 + 16.2) =\frac{1}{2} * 32.1 = 16.05

x_4 = \frac{1}{2}(16.2 + 16.5) =\frac{1}{2} * 32.7 = 16.35

x_5 = \frac{1}{2}(16.5 + 16.8) =\frac{1}{2} * 33.3 = 16.65

So, we have:

\begin{array}{cccccc}x & {15.45} & {15.75} & {16.05} & {16.35} & {16.65} \ \\ f & {14} & {25} & {84} & {18} & {9} \ \end{array}

Calculate mean

\bar x = \frac{\sum fx}{\sum f}

\bar x = \frac{15.45 * 14 + 15.75 * 25 + 16.05 * 84 + 16.35 * 18 + 16.65 * 9}{14 + 25 + 84 + 18 + 9}

\bar x = \frac{2402.4}{150}

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The standard deviation is:

\sigma = \sqrt{\frac{\sum(x_i - \bar x)^2}{\sum f}}

\sigma = \sqrt{\frac{(15.45 - 16.016)^2+ (15.75  - 16.016)^2+ (16.05  - 16.016)^2+ (16.35   - 16.016)^2+ (16.65  - 16.016)^2}{14 + 25 + 84 + 18 + 9}}

\sigma = \sqrt{\frac{0.90578}{150}}

\sigma = \sqrt{0.00603853333}

\sigma = 0.07770

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2 years ago
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