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3 years ago

8.EE.8

Mathematics

1 answer:

IceJOKER [234]3 years ago

4 0

For the first system, we have

1 - 3x + 3y = -8

-3x + 3y = -9

The second equation, however, tells us

-3x + 3y = 13

but -9 ≠ 13, so this system has no solution.

For the second system, notice that multiplying both sides of

4x - 8y = 6

by 1/2 gives

2x - 4y = 3

which is identical to the other equation in the system. Then all point (x, y) that lie on this line are solutions to the system, meaning there are infinitely many solutions.

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the equation 3s equals 21 can be used to find the number of students s in each van on a field trip how many students are in each

Leno4ka [110]

Answer:

to be honest I don't know sorry

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2 years ago

There are 5 very different seats in a car. In how many ways can 5 different people be seated in the car for a road trip if only

avanturin [10]

Answer:

Step-by-step explanation:

Let A and B be the two people who are able to drive. If A is driving, there are 4! ways to arrange the remaining peoplein the car seats. If B is driving, there are also 4! ways to arrange the remaining people. The number of arrangements 'n' is:

$n=2*4!\\n=2*4*3*2*1\\n=48\ ways$

They can be arranged in 48 ways.

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3 years ago

Suppose you do not know the population mean fee charged to H&R Block customers last year. Instead, suppose you take a sample

puteri [66]

Answer:

i $\to$ a

$n = 96040000$

i $\to$ b

$n_1 =24010000$

i $\to$ c

$n_2 =41602500$

ii $\to$ a

$E = 58.16$

ii $\to$ b

$291.84 < \mu < 408.16$ \

ii $\to$ c

There is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval

Step-by-step explanation:

From the question we are told that

The sample size is $n = 8$

The sample mean is $\= x = \$ 350$

The sample standard deviation is $\$ 100$

Considering question i

i $\to$ a

At $E = 0.02$

given that the confidence level is 95% = 0.95

the level of significance would be $\alpha =1-0.95 = 0.05$

The critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha }{2} } = 1.96$

So the sample size is mathematically evaluated as

$n = [ \frac{Z_{\frac{\alpha }{2} } * \sigma }{E} ]^2$

=> $n =[ \frac{ 1.96 * 100}{ 0.02} ]^2$

=> $n = 96040000$

i $\to$ b

At $E_1 = 0.04$ and confidence level = 95% => $\alpha_1 = 0.05$ => $Z_{\frac{\alpha_1 }{2} } = 1.96$

$n_1 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_1} ]^2$

=> $n_1 =[ \frac{ 1.96 * 100}{ 0.04} ]^2$

=> $n_1 =24010000$

i $\to$ c

At $E_2 = 0.04$ confidence level = 99% => $\alpha_2 = 0.01$

The critical value of $\frac{\alpha_2 }{2}$ from the normal distribution table is

$Z_{\frac{ \alpha_2 }{2} } = 2.58$

=> $n_2 = [ \frac{Z_{\frac{\alpha_2 }{2} } * \sigma }{E_2} ]^2$

=> $n_2 =[ \frac{ 2.58 * 100}{ 0.04} ]^2$

=> $n_2 =41602500$

Considering ii

Given that the level of significance is $\alpha = 0.10$

Then the critical value of $\frac{\alpha }{2}$ from the normal distribution table is

$Z_{\frac{\alpha }{2} } = 1.645$

Generally the margin of error is mathematically represented as

$E = Z_{\frac{\alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

substituting values

$E = 1.645 * \frac{100 }{\sqrt{8} }$

$E = 58.16$

Generally the 90% confidence interval is mathematically evaluated as

$\= x - E < \mu < \= x + E$

=> $350 - 58.16 < \mu < 350 + 58.16$

=> $291.84 < \mu < 408.16$

So the interpretation is that there is 90% confidence that the mean fee charged to H&R Block customers last year is in the interval .So there is insufficient evidence to conclude that the analyst is right because the population mean fee by the analyst does not fall within the confidence interval.

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3 years ago

Which term describes the point where the three angle bisectors of a triangle intersect?

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The term that describes the point where the three angle bisectors of a triangle intersect is known as insector

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2 years ago

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Tom has a large photo he wants to shrink to wallet sized it's with is 20 cm and its length is 30 cm. If he wants the width to be

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The width was 20 cm and was brought down to 5 cm, you can see that the pictures width was shrunk down 4 times because 20 divide by 4 is 5 so to find the length you would divide 30 by 4 and get 7.5 cm as your answer.

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2 years ago