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2 years ago

Please help !!

Physics

1 answer:

ExtremeBDS [4]2 years ago

3 0

Answer:

Just as the angles of the sun, moon and Earth affect tidal heights over the course of a lunar month, so do their distances to one another. Because the moon follows an elliptical path around the Earth, the distance between them varies by about 31,000 miles over the course of a month.

Hope this helped, have a nice rest of your day!

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a cruise ship travels directly toward the dock with a velocity of 15 m/s relative to the water. A passenger walks 3 m/s in the s

solong [7]

Answer:

Explanation:

i believe a if not c

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2 years ago

A 75 kg baseball player runs at a velocity of 6 m/s before sliding to a stop at second base. a. What is the kinetic energy of th

lana [24]

Answer:

a. $\displaystyle k_o=1350\ J$

b. $\displaystyle k_1=0\ J$

c. $\Delta k=-1350\ J$

d. $W=-1350\ J$

e. $F=-675\ N$

Explanation:

<u>Work and Kinetic Energy </u>

When an object moves at a certain velocity v0 and changes it to v1, a change in its kinetic energy is achieved:

$\Delta k=k_1-k_0$

Knowing that

$\displaystyle k=\frac{mv^2}{2}$

We have

$\displaystyle \Delta k=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

The work done by the force who caused the change of velocity (acceleration) is

$\displaystyle W=\frac{mv_1^2}{2}-\frac{mv_0^2}{2}$

If we know the distance x traveled by the object, the work can also be calculated by

$W=F.x$

Being F the force responsible for the change of velocity

The 75 kg baseball player has an initial velocity of 6 m/s, then he slides and stops

a. Before the slide, his initial kinetic energy is

$\displaystyle k_o=\frac{mv_0^2}{2}$

$\displaystyle k_o=\frac{(75)6^2}{2}$

$\boxed{\displaystyle k_o=1350\ J}$

b. Once he reaches the base, the player is at rest, thus his final kinetic energy is

$\displaystyle k_1=\frac{(75)0^2}{2}$

$\boxed{\displaystyle k_1=0\ J}$

c. The change of kinetic energy is

$\Delta k=k_1-k_0=0\ J-1350\ J$

$\boxed{\Delta k=-1350\ J}$

d. The work done by friction to stop the player is

$W=\Delta k=k_1-k_0$

$\boxed{W=-1350\ J}$

e. We compute the force of friction by using

$W=F.x$

and solving for x

$\displaystyle F=\frac{W}{x}$

$\displaystyle F=\frac{-1350\ J}{2\ m}$

$\boxed{F=-675\ N}$

The negative sign indicates the force is against movement

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2 years ago

Explain what happens to the average kinetic energy, thermal energy, and temperature of a substance when the particles in the sub

pochemuha

Kinetic, thermal, and the temperature of the substance all decrease when the particles slow down.

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3 years ago

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What happens if someone walks between you and the heater? Can you still feel its warmth?

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No, for that moment

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3 years ago

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if the aud daclrck clock has a frequency of 48 khz. what value would you set the constant in the stretch timer of the button deb

timama [110]

To obtain a delay of 360 ms for a clock with frequency of 48 khz, we must set the constant in the button debounce circuit's stretch timer to the value of 1720.

Set the comparator value of the debounce circuit's stretch timer to have a delay of one second to examine the impact of the pulse stretch timer. To do this, set the stretch compare megafunction's constant value to 4800

For 1 second = 48000

For 360 ms = $\frac{4800}{1}$ × 360 × $10^{-3}$

= 17280

Some pupils struggle with the concept of switch bounce. They are never less than amazed when we use the oscilloscope to view a switch's output. Depending on the situation, I utilize either hardware or software for the debounce solution. A capacitor and resistor are frequently inexpensive in terms of price and board area, thus I typically choose a hardware solution to free up my inexpensive microcontroller to perform other crucial tasks.

Learn more about Debounce circuit's stretch timer here:

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1 year ago