<span>uclear Physicist specializing inoffensive weapons systems - pretty obvious why this would be.
Highway Engineer - again, pretty obvious reasons.</span>
It is possible for a wooden ruler to be worn out at the edge. If such a ruler is used for measurement, there will be error in the measurement due to the inaccuracy of the ruler. To avoid this, some rulers do not start with zero at the edge.
Answer:
0.882 m/s average velocity and 1.71 m/s average speed
Explanation:
The dog travels a total of 35 m west and 110 m east.
110-35 = 75 m east of the starting position. Since velocity is a vector you must consider its first and final position and not the total distance traveled.
75 m / 85 s = 0.882 m/s average velocity
Speed is not concerned with direction so we instead add the total distance traveled which is 35+110 = 145 m. We then perform the same operation as before and divide by the time it took to run this distance.
145 m / 85 s = 1.71 m/s average speed
Answer:
The normal force is the force that surfaces exert to prevent solid objects from passing through each other. If the object is at rest, the net force on the object is equal to zero. Therefore, the downward force (weight) must be equal to the upward force (normal force).
Answer:
a) Shadow distance
10 cm in front of the mirror.
b) Zoom in the shadow
The shadow formed is the same height as the object and is placed also at the centre of curvature of the mirror as shown in the attached image to this solution.
c) The nature of the shadow
The shadow formed is real, inverted, same size as the object and formed at the centre of curvature.
Explanation:
English Translation
Objects as high as 3 cm are placed at a distance of 10 cm in front of a concave mirror with 10 cm curvature. Determine:
a) Shadow distance
b) Zoom in the shadow
c) The nature of the shadow
Solution
The mirror equation is given as
(1/f) = (1/v) + (1/u)
f = focal length of the mirror = (radius of curvature)/2 = 10/2 = 5 cm
v = image distance = ?
u = object distance = 10 cm
We can then calculate the shadow' s distance from the mirror thus
(1/5) = (1/v) + (1/10)
(1/v) = 0.2 - 0.1 = 0.1
v = (1/0.1) = 10 cm
b) Zoom in the shadow
Since the object is placed at the centre of curvature, as shown in the attached image, the image is formed at a point of intersection of rays. The image formed is the same height as the object and is placed also at the centre of curvature of the mirror.
c) The nature of the shadow
Since the mirror is a concave mirror, the image is real and formed in front of the mirror. The image is also inverted and formed at the centre of curvature of the mirror.
Hope this Helps!!!