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aalyn [17]
2 years ago
15

A zone reconnaissance involves a directed effort to obtain detailed information on all routes, obstacles, terrain, enemy forces,

or specific civil considerations within a zone defined by boundaries to include obstacles (existing and reinforcing) as well as areas of CBRN contamination. True or false?
Physics
1 answer:
son4ous [18]2 years ago
7 0

Answer:

It is True

Explanation:.

A  commander assigns a zone reconnaissance mission when he seeks additional information on a zone before committing other forces in the zone. It is appropriate when the enemy situation is vague,  existing knowledge of the terrain is limited, or combat operations have altered the terrain. A zone  reconnaissance could include several route or area reconnaissance missions assigned to subordinate units.

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Answer:

the answer is c. centripetal force

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99 POINT QUESTION PLUS BRAINLIEST!!!
ollegr [7]
Well i cant <span>explain it as well as i would like, if i did it would make no sens, but the answer should be (C.) 60m. but i`m only 95% sure its the answer. i hope this helps!</span>
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2 years ago
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A suspension bridge is 60.0 m above the level base of a gorge. A stone is thrown or dropped from the bridge. Ignore air resistan
Alexxx [7]

Answer:

a)t_{1}=3.49s

b)t_{2}=2.00s

c)Xmax=80.71m

Explanation:

<u>a)Kinematics equation for the Stone, dropped:</u>

v(t)=v_{o}-g*t

y(t)=y_{o}+v_{o}t-1/2*g*t^{2}

y_{o}=h=60m       initial position is bridge height

v_{o}=0m/s       the stone is dropped

The ball reaches the ground, y=0, at t=t1:

0=h-1/2*g*t_{1}^{2}

t_{1}=\sqrt{2h/g}=\sqrt{2*60/9.83}=3.49s

<u>b)Kinematics equation for the Stone, with a initial speed of 20m/s:</u>

v(t)=v_{o}-g*t

y(t)=y_{o}+v_{o}t-1/2*g*t^{2}

y_{o}=h=60m       initial position is bridge height

v_{o}=-20m/s       the stone is thrown straight down

The ball reaches the ground, y=0, at t=t1:

0=h+v_{o}t_{2}-1/2*g*t_{2}^{2}

0=60-20t_{2}-1/2*9.83*t_{2}^{2}

t2=-6.01       this solution does not have physical sense

t2=2.00

<u>c)Kinematics equation for the Stone, with a initial speed of 20m/s with an angle of 30° above the horizontal:</u>

v(t)=v_{o}-g*t

y(t)=y_{o}+v_{o}t-1/2*g*t^{2}

y_{o}=h=60m       initial position is bridge height

v_{o}=20sin(30)=10m/s       the stone is thrown with an angle of 30° above the horizontal

The ball reaches the ground, y=0, at t=t3:

0=h+v_{o}t_{3}-1/2*g*t_{3}^{2}

0=60+10t_{3}-1/2*9.83*t_{3}^{2}

t3=-2.62       this solution does not have physical sense

t3=4.66

the movement in x:

v=constant=20cos(30)m/s

x(t)=v*t

Xmax=v*t3=20cos(30)*4.66=80.71m

3 0
3 years ago
An ambulance is traveling east at 51.6 m/s. Behind it there is a car traveling along the same direction at 32.3 m/s. The ambulan
alekssr [168]
Speed of source=51.6=s
speed of observer=32.3=o
original frequency=615=F
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frequency hear by observer=f
f={ (S+o) /(S+51.6) }/F
f=585
Wavelength=5x 10^{5}  m
7 0
3 years ago
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