Carl is eating lunch at his favorite cafe when his friend Isaac calls and says he wants to meet him. Isaac is calling from a cit
1 answer:
Answer:
106.52 minutes
Explanation:
Given:
Initial distance between Carl and Isaac = 175 miles
speed of Isaac = 65 mph
Speed of Carl = 50 mph
Now, the Carl starts after 35 minutes, but the Isaac has already started so the distance covered by Isaac in 35 minutes will be
=
= 37.91 miles
Therefore,
the distance left between Isaac and Carl = 175 - 37.91 = 137.09 miles
Since Isaac and Carl are moving towards each other,
therefore the relative speed between the both = 65 + 50 = 115 mph
Hence, the time taken to meet =
or
The time taken to meet = 1.192 hours
or
The time taken = 1.192 × 60 = 71.52 minutes
Therefore the total time Isaac have been travelling = 71.52 + 35
= 106.52 minutes
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Complete question:
A 50 m length of coaxial cable has a charged inner conductor (with charge +8.5 µC and radius 1.304 mm) and a surrounding oppositely charged conductor (with charge −8.5 µC and radius 9.249 mm).
Required:
What is the magnitude of the electric field halfway between the two cylindrical conductors? The Coulomb constant is 8.98755 × 10^9 N.m^2 . Assume the region between the conductors is air, and neglect end effects. Answer in units of V/m.
Answer:
The magnitude of the electric field halfway between the two cylindrical conductors is 5.793 x 10⁵ V/m
Explanation:
Given;
charge of the coaxial capable, Q = 8.5 µC = 8.5 x 10⁻⁶ C
length of the conductor, L = 50 m
inner radius, r₁ = 1.304 mm
outer radius, r₂ = 9.249 mm
The magnitude of the electric field halfway between the two cylindrical conductors is given by;
Where;
λ is linear charge density or charge per unit length
r is the distance halfway between the two cylindrical conductors
The magnitude of the electric field is now given as;
Therefore, the magnitude of the electric field halfway between the two cylindrical conductors is 5.793 x 10⁵ V/m