The law of harmonies is referred to as _____.
1 answer:
Answer:
Kepler's third law
Explanation:
As per Kepler's third law all planets revolve around the Sun in such a way that their square of time period of revolution around the Sun is proportional to the cube of the mean radius.
It is given as
here
c = proportionality constant
R = mean radius
T = time period around the sun
So here all celestial body and all planets revolve as per the Kepler's third law which is also known as law of harmonies
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By using first and third equation of motion, the number of revolutions the tire makes during this motion is 43 rev.
ANGULAR MOTION
Since the car accelerate from rest, initial velocity will be zero.
Given that a car accelerates uniformly from rest and reaches a speed of 24.3 m/s in 9.1 s. The following are the given parameters
- Initial velocity U = 0
- Final velocity V = 24.3 m/s
- Time t = 9.1 s
If the diameter of a tire is 80.2 cm, to find the number of revolutions the tire makes during this motion, we must first calculate the distance travelled by the car by using first and third equation of motion of the car.
First equation
V = U + at
Substitute all necessary parameters into the equation.
24.3 = 0 + 9.1a
a = 24.3/9.1
a = 2.67 m/
Third Equation of motion
Substitute all the necessary parameters
= 0 + 2 x 2.67 x S
590.49 = 5.34S
S = 590.49 / 5.34
S = 110.58 m.
Given that the diameter of a tire is 80.2 cm,
the radius (r) will be 80.2/2 = 40.1 cm
convert it to meter
r = 40.1/100 = 0.401 m
The Circumference of the tire = 2r
Circumference = 2 x 3.143 x 0.401
Circumference = 2.52 m
Assuming no slipping, number of revolutions = 110.58/2.52
Number of revolutions = 43.89 rev.
Number of revolutions = 43 rev.
Therefore, the number of revolutions the tire makes during this motion is 43 rev.
Learn more about circular motion here: brainly.com/question/6860269