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Mazyrski [523]
4 years ago
12

Jeandre said |3| equals |-3|. Is Jeandre correct? Use a number line and words to support your answer.

Mathematics
1 answer:
den301095 [7]4 years ago
8 0
Yes, he is correct and he is referring to the absolute values of number 3 and -3. And by absolute value, this is the distance of the number from the origin zero (0) which is symbolized by two vertical lines, as |3| or |-3| is equal to 3. 

the picture shows a number line where green is the origin zero (0). The purple line is the distance between 0 and 3 which is 3. The pink one is the distance of -3 from 0 which is also 3. Therefore,  |3| equals |-3|

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Could somebody please help me?
Ray Of Light [21]

When multiplying exponential terms with the same base, the exponents can be added:

3+-5

3-5

-2

5^-2

When raising a value to a negative exponent, it can be rewritten as a fraction.  Therefore, the answer is:

1/5^2

Hope this helps!!

6 0
3 years ago
Read 2 more answers
A bank loaned out ​$18,000​, part of it at the rate of 9% per year and the rest at 19% per year. If the interest received in one
Galina-37 [17]
X * 0.09 + (18000-x)*0.19= 3000
x*(-0.1) + 3420 = 3000
x = -420/(-0.1)
x = 4200

The bank loaned out $4,200 at 9%
4 0
3 years ago
Art Club Flyer
Finger [1]

The area of Erin's circle to the nearest hundredth is 50.24 in².

<h3>What is the area of the circle?
</h3>

A circle is a bounded figure which points from its center to its circumference is equidistant.

Area of a circle = πr²

Where :

  • π = pi = 3.14
  • R = radius

3.14 X 4²

(3.14) (4) (4) = 50.24 in²

To learn more about the area of a circle, please check: brainly.com/question/14351152

#SPJ1

8 0
2 years ago
Read 2 more answers
wo balls are chosen randomly from an um containing 8 white, 4 black,and 2 orange balls. Suppose that we win $2 for each black ba
umka21 [38]

Answer:

The probability distribution is shown below.

Step-by-step explanation:

The urn consists of 8 white (<em>W</em>), 4 black (<em>B</em>) and 2 orange (<em>O</em>) balls.

The winning and losing criteria are:

  • Win $2 for each black ball selected.
  • Lose $1 for each white ball selected.

There are 8 + 4 + 2 = 14 balls in the urn.

The number of ways to select two balls is, {14\choose 2}=91 ways.

The distribution of amount won or lost is as follows:

Outcomes: WW  WO  WB  BB  BO  OO

X:                 -2      -1      1      4     2      0

Compute the probability of selecting 2 white balls as follows:

The number of ways to select 2 white balls is, {8\choose 2}=28 ways.

The probability of WW is,

P(WW)=\frac{n(WW)}{N}=\frac{28}{91}=0.3077

Compute the probability of selecting 1 white ball and 1 orange ball as follows:

The number of ways to select 1 white ball and 1 orange ball is, {8\choose 1}\times {2\choose 1}=16 ways.

The probability of WO is,

P(WO)=\frac{n(WO)}{N}=\frac{16}{91}=0.1758

Compute the probability of selecting 1 white ball and 1 black ball as follows:

The number of ways to select 1 white ball and 1 black ball is, {8\choose 1}\times {4\choose 1}=32 ways.

The probability of WB is,

P(WB)=\frac{n(WB)}{N}=\frac{32}{91}=0.3516

Compute the probability of selecting 2 black balls as follows:

The number of ways to select 2 black balls is, {4\choose 2}=6 ways.

The probability of BB is,

P(BB)=\frac{n(BB)}{N}=\frac{6}{91}=0.0659

Compute the probability of selecting 1 black ball and 1 orange ball as follows:

The number of ways to select 1 black ball and 1 orange ball is, {4\choose 1}\times {2\choose 1}=8 ways.

The probability of BO is,

P(BO)=\frac{n(BO)}{N}=\frac{8}{91}=0.0879

Compute the probability of selecting 2 orange balls as follows:

The number of ways to select 2 orange balls is, {2\choose 2}=1 ways.

The probability of OO is,

P(OO)=\frac{n(OO)}{N}=\frac{1}{91}=0.0110

The probability distribution of <em>X</em> is:

Outcomes:    WW     WO        WB         BB        BO         OO

X:                    -2          -1            1            4            2            0

P (X):           0.3077  0.1758  0.3516  0.0659  0.0879  0.0110

3 0
4 years ago
Tessellation that use more than one type of regular polygon are called regular tessellations
NARA [144]

Answer:

FALSE

Step-by-step explanation:

A tessellation refest to a shape that is repeated over and over again covering a plane without any gaps or overlaps. The statement is false given that regular tessellations use only one polygon. Semi-regular tessellations are created with more than one type of regular polygon.

8 0
4 years ago
Read 2 more answers
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