Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher
I would think Kaylee is 5 since 12 divided by 3 is 4 and 4 * 2 is 8, and 8-3 is 5. So, I would think Kaylee is 5.
6 hikers = 4.5 lbs of trail mix
4.5 divided by 6= .75 lbs each hiker.
Answer:
60.4
Step-by-step explanation:
90-29.6= 60.4
complimentary means either of two angles whose sum is 90°.