All categories

3 years ago

A pair of badminton rackets was originally marked at $30 and has been sold $24. What was the percent of discount

Mathematics

1 answer:

erastovalidia [21]3 years ago

4 0

Answer:

20%

Step-by-step explanation:

Discount= $30 - $24 = $6

Discount%= $\frac{6}{30}$ × $\frac{100}{1}$ = 20%

You might be interested in

What is the length of CD ? In this diagram ABC EDC ?<br> Please help !!!!

n200080 [17]

Answer:
CD = x = 4 units

Explanation:
We are given that the two triangles are similar. This means that we can set the similarity proportionality as follows:
$\frac{BC}{CD} = \frac{CA}{CE} = \frac{AB}{ED}$

W e have:
BC = 20 - x
AC = 20
CD = x
CE = 5

Substitute in the above proportionality and solve for x as follows:
$\frac{20-x}{x} = \frac{20}{5} = 4$

4x = 20 - x
5x = 20
x = 4

Based on he above:
CD = 4 units
BC = 20 - x = 20 - 4 = 16 units

Hope this helps :)

5 0

3 years ago

Read 2 more answers

Stephanie just redecorated her bedroom. She wants to paint her door green but needs to know the surface area of the door to see

Alona [7]

Answer:The surface area of the door is 33,680

Step-by-step explanation:

The answer is correct.

3 0

3 years ago

Jordan solved the equation −7x + 25 = 48; his work is shown below. Identify the error and where it was made.

fenix001 [56]

Answer:

step 3: he should have divided both sides by -7

8 0

3 years ago

If possible help me in this. I need to find the two odd numbers...

Lelechka [254]

Part (a)

Consecutive odd integers are integers that odd and they follow one right after another. If x is odd, then x+2 is the next odd integer

For example, if x = 7, then x+2 = 9 is right after.

<h3>Answer: x+2</h3>

========================================================

Part (b)

The consecutive odd integers we're dealing with are x and x+2.

Their squares are x^2 and (x+2)^2, and these squares add to 394.

<h3>Answer: x^2 + (x+2)^2 = 394</h3>

========================================================

Part (c)

We'll solve the equation we just set up.

x^2 + (x+2)^2 = 394

x^2 + x^2 + 4x + 4 = 394

2x^2+4x+4-394 = 0

2x^2+4x-390 = 0

2(x^2 + 2x - 195) = 0

x^2 + 2x - 195 = 0

You could factor this, but the quadratic formula avoids trial and error.

Use a = 1, b = 2, c = -195 in the quadratic formula.

$x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\x = \frac{-(2)\pm\sqrt{(2)^2-4(1)(-195)}}{2(1)}\\\\x = \frac{-2\pm\sqrt{784}}{2}\\\\x = \frac{-2\pm28}{2}\\\\x = \frac{-2+28}{2} \ \text{ or } \ x = \frac{-2-28}{2}\\\\x = \frac{26}{2} \ \text{ or } \ x = \frac{-30}{2}\\\\x = 13 \ \text{ or } \ x = -15\\\\$

If x = 13, then x+2 = 13+2 = 15

Then note how x^2 + (x+2)^2 = 13^2 + 15^2 = 169 + 225 = 394

Or we could have x = -15 which leads to x+2 = -15+2 = -13

So, x^2 + (x+2)^2 = (-15)^2 + (-13)^2 = 225 + 169 = 394

We get the same thing either way.

<h3>Answer: Either 13, 15 or -15, -13</h3>

4 0

3 years ago

Name two integers whose quotient is -7

Andrei [34K]

Answer:

1 and -7

Step-by-step explanation:

3 0

3 years ago