I believe it would be an unbalanced force. Because the forces are unbalanced, one side is stronger and, therefore, the object will move.
Answer:
a) Ws = 2.548 J
b) Wf = 1.153 J
c) v = 1.923 m / s
Explanation:
a) The work done by the spring force
Ws = ½ * k * x²
Ws = ½ * 260 N/m *0.14² m
Ws = 2.548J
b) The increase in thermal energy can by find using
Et = Wf
Wf = µ * m *g * x
Wf = 0.42 * 2.0 kg *9.8 m/s² * 0.14m
Wf = 1.153 J
c) The speed just as the block reaches can by fin using
EK = Ws + Et
Ek = ( 2.548 + 1.153 ) J = 3.7 J
Ek = ½ * m * v²
v² = 2* Ek / m
v = √[2 * 3.7 J / 2.0 kg]
v = 1.923 m / s
1. Air resistance (therefore, the air density, shape (aerodynamic or not), and surface area affected
2. The gravitational acceleration constant (g = 9.8 m/s^2 on Earth)
Answer:
Explanation:
The problem is based on interference in thin films
refractive index of water is more than given oil so there will be phase change of π at upper and lower layer of the film .
a )
for constructive interference , the condition is
2μt = nλ where t is thickness of layer , μ is refractive index , λ is wavelength and n is order of the fringe
Putting the values
2 x 1.27 t = n x 640
2 x 1.27 t = 640 ( for minimum thickness n = 1 )
t = 252 nm .
b )
2 x 1.27 t = m₁ λ₁
for destructive interference
2μt = (2m₂+1)λ₂/2
2 x 1.27 t =(2m₂+1)λ₂/2
m₁ λ₁ = (2m₂+1)λ₂/2
2m₁λ₁ = (2m₂+1)λ₂
2m₁ / (2m₂+1) = λ₂ / λ₁
2m₁ / (2m₂+1) = 548/ 640
2m₁ / (2m₂+1) = .85625
2m₁ = .85625 (2m₂+1)
This is the required relation between m₁ and m₂
Answer:
2a. 24 m³
2b. 19200 Kg
2c. 192000 N
2d. 16000 N/m²
Explanation:
2a. Determination of the volume of paraffin.
Length (L) = 4 m
Width (W) = 3 m
Height (H) = 2 m
Volume (V) =?
V = L × W × H
V = 4 × 3 × 2
V = 24 m³
Therefore the volume of paraffin is 24 m³
2b. Determination of the mass of paraffin.
Volume (V) = 24 m³
Density (ρ) = 800 Kg/m³
Mass (m) =?
ρ = m / V
800 = m / 24
Cross multiply
m = 800 × 24
m = 19200 Kg
Therefore, the mass of paraffin is 19200 Kg
2c. Determination of the weight of paraffin.
Mass (m) = 19200 Kg
Acceleration due to gravity (g) = 10 N/Kg
Weight (W) =?
W = m × g
W = 19200 × 10
W = 192000 N
Therefore, the weight of paraffin is 192000 N
2d. Determination of the pressure.
Density (ρ) = 800 Kg/m³
Depth (h) = 2 m
Acceleration due to gravity (g) = 10 N/Kg
Pressure (P) =?
P = ρgh
P = 800 × 10 × 2
P = 16000 N/m²
