It's called covelant bonding
Answer:
acceleraions 5.76g and 20.55g
Explanation:
This constant acceleration exercise can be solved using the kinematic equations in one dimension
Vf = Vo + a t
As part of the rest Vo = 0
a = Vf / t
a = 282/5
a = 56.4 m / s2
In relation to the acceleration of gravity
a ’= a / g = 56.4 / 9.8
a ’= 5.76g
To calculate the acceleration to stop we use the same formula
a2 = 282 / 1.40
a2 = 201.4 m / s2
This acceleration of gravity acceleration function is
a2 ’= 201.4 / 9.8
a2 ’= 20.55g
B) It is turned by water to produce a direct current....... hope it helps :)
Answer:
n = 10 beats
Explanation:
Given:
- Frequency of note f1 = 151 Hz
- Frequency of note f2 = 155 Hz
- The total time they ring t = 2.5 s
Find:
How many beats are heard
Solution:
- The frequency of beat (fb) is the difference between the two frequencies of notes as follows:
fb = f2 - f1
fb = 155 - 151
fb = 4 Hz
- The number of beats per second is also called beat frequency:
n = fb*t
n = 4*2.5
n = 10 beats
Answer:
i think solar, space
Explanation:
please tell me if i got it right
