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3 years ago

How do streams change as they flow from mountains down to plains? Plz help URGENT I need it today

Physics

1 answer:

lisov135 [29]3 years ago

5 0

They start as one stream, then get curvier, then empy into a delta. A delta is a ton of streams of water. It is one, then empties out into a ton of streams.
~Deceptiøn

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6. Sandy adds 3 sugar packets to her tea in order to make it sweeter. She stirs in the sugar and then takes a sip. She notices t

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Answer:

C.Supersaturated

Explanation:

There are three types of solution:

SATURATED SOLUTION:

It is the solution that contains maximum amount of solute dissolved in a solution in normal conditions.

UNSATURATED SOLUTION:

It is the solution that contains less than the maximum amount of solute dissolved in a solution in normal conditions. It has space for more solute to be dissolved in it.

SUPERSATURATED SOLUTION:

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3 years ago

If the wavelength is changed to λ/2, does the central spot remain bright, does the central spot become dark, or do the fringes d

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Answer:The central spot becomes Dark

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3 years ago

A 2 kg blue car is moving 6 m/s to the right and collides with a 3 kg red car that is moving 2 m/s to the left. The cars collide

snow_lady [41]

Answer:

Their velocity after the collision is 1.2 m/s, to the right.

Explanation:

Given;

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mass of the red car, m₂ = 3 kg

initial velocity of the red car, u₂ = 2 m/s

let the blue car moving to the right be in positive direction

also, let the red car moving to the left be in negative direction

Apply the principle of conservation of linear momentum for inelastic collision.

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where;

v is their velocity after the collision

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12 - 6 = 5v

6 = 5v

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Therefore, their velocity after the collision is 1.2 m/s, to the right.

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3 years ago

Part complete Sound with frequency 1240 Hz leaves a room through a doorway with a width of 1.11 m . At what minimum angle relati

Sedbober [7]

Answer:

14.43° or 0.25184 rad

Explanation:

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f = Frequency = 1240 Hz

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$\lambda=\frac{v}{f}\\\Rightarrow \lambda=\frac{343}{1240}\\\Rightarrow \lambda=0.2766\ m$

In the case of Fraunhofer diffraction we have the relation

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