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iVinArrow [24]
3 years ago
11

When you jump from an elevated position you usually bend your knees upon reaching the ground. By doing this, you make the time o

f the impact about 10 times as great as for a stiff-legged landing. In this way the average force your body experiences is
Physics
1 answer:
Len [333]3 years ago
3 0

Answer:

10 time smaller

Explanation:

Since the average force of impact is the impulse divided by the time of impact:

F = \frac{\Delta P}{\Delta t}

whereas impulse is the change of momentum (from full to rest) which is constant and independent of the time of impact. So if you make the time of the impact about 10 times as great as for a stiff-legged landing, the average force that you experience would be 10 times smaller.

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Rearrange the Coulomb's Law formula to find distance(r)
lesantik [10]
<span>Coulomb's law describes the magnitude of the electrostatic force between two electric charges. The Coulomb's law formula is:
  <span>F = Ke * q1 * q2 / r2</span>

Where:
  q1: Charge of object 1
  q2: Charge of object 2
  r: Distance between the two objects
  F: Force between the two objects. A positive force implies a repulsive interaction, while a negative force implies an attractive interaction
  Ke = Coulomb Constant, 8.9875517873681764 * 109 N.m2.C<span>-2
</span>
Coulomb's Law Examples:
What is the magnitude of the force between two protons which are 1.6E10-6 meters apart?

The charge of 1 proton is +1e (+1.602E-19 C).

F = 8.9875517873681764 * 109 * 1.602E-19 * 1.602E-19 / (1.6E-6 * 1.6 E-6) = 9 * 10-17 N


Source- http://www.endmemo.com/physics/coulomb.php




f = k (q^1)(q^2)/r^2

both sides by r^2 Multiply
fr^2/r^2 = kq^3/r^2

both sides by r^2 divide 
f = kq^3/r^2


Answer:
f = kq^3/r^2



Hope this helps!!!!


</span>
6 0
3 years ago
Read 2 more answers
A(n) 930 N crate is being pushed across a level floor by a force of 400 N at an angle of 20◦ above the horizontal. The coefficie
Nana76 [90]

Answer:

The magnitude of the acceleration of the box is 2.291\,\frac{m}{s^{2}}.

Explanation:

The free body diagram of the crate is included as attachment, whose equations of equilibrium are described below:

\Sigma F_{x} = P\cdot \cos 20^{\circ} - \mu_{k}\cdot N = \left(\frac{W}{g}\right)\cdot a

\Sigma F_{y} = P\cdot \sin 20^{\circ} + N - W = 0

From second equation of equilibrium we find an expression for the normal force and find the respective value:

N = W - P \cdot \sin 20^{\circ}

N = 930\,N - 400\cdot \sin 20^{\circ}\,N

N = 793.192\,N

Lastly, the acceleration experimented by the crate during pushing is cleared in the first equation of equilibrium and consequently calculated:

a = \frac{P\cdot \cos 20^{\circ}-\mu_{k}\cdot N}{\frac{W}{g} }

a = \frac{400\cdot \cos 20^{\circ}\,N-0.20\cdot (793.192\,N)}{\frac{930\,N}{9.807\,\frac{m}{s^{2}} } }

a = 2.291\,\frac{m}{s^{2}}

The magnitude of the acceleration of the box is 2.291\,\frac{m}{s^{2}}.

3 0
2 years ago
I've been on this for a while please help me
True [87]

Answer: Student 2

Explanation: Iron nail and a paperclip are conductors because they are made of metal. A rock, rubber band, and wooden stick are insulators because they cannot conduct electricity.

7 0
2 years ago
I'm looking for the answers for 4-6 and how to do them. I have some answers already but I'm very unsure of them. Thank you!
coldgirl [10]
Answer to 4: E

Answer to 6: D
7 0
3 years ago
How far did a frog jump if he travels at a rate of 2.1 m/s for 10 seconds?
Anestetic [448]

Answer:

21 m

Explanation:

The motion of the frog is a uniform motion (constant speed), therefore we can find the distance travelled by using

d=vt

where

d is the distance covered

v is the speed

t is the time

The frog in this problem has a speed of

v = 2.1 m/s

and therefore, after t = 10 s, the distance it covered is

d=(2.1)(10)=21 m

3 0
3 years ago
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