<span>Coulomb's law describes the magnitude of the electrostatic force between two electric charges.
The Coulomb's law formula is:
<span>F = Ke * q1 * q2 / r2</span>
Where:
q1: Charge of object 1
q2: Charge of object 2
r: Distance between the two objects
F: Force between the two objects. A positive force implies a repulsive interaction, while a negative force implies an attractive interaction
Ke = Coulomb Constant, 8.9875517873681764 * 109 N.m2.C<span>-2
</span>
Coulomb's Law Examples:
What is the magnitude of the force between two protons which are 1.6E10-6 meters apart?
The charge of 1 proton is +1e (+1.602E-19 C).
F = 8.9875517873681764 * 109 * 1.602E-19 * 1.602E-19 / (1.6E-6 * 1.6 E-6) = 9 * 10-17 N
Source- http://www.endmemo.com/physics/coulomb.php
f = k (q^1)(q^2)/r^2
both sides by r^2 Multiply
fr^2/r^2 = kq^3/r^2
both sides by r^2 divide
f = kq^3/r^2
Answer:
f = kq^3/r^2
Hope this helps!!!!
</span>
Answer:
The magnitude of the acceleration of the box is
.
Explanation:
The free body diagram of the crate is included as attachment, whose equations of equilibrium are described below:


From second equation of equilibrium we find an expression for the normal force and find the respective value:



Lastly, the acceleration experimented by the crate during pushing is cleared in the first equation of equilibrium and consequently calculated:



The magnitude of the acceleration of the box is
.
Answer: Student 2
Explanation: Iron nail and a paperclip are conductors because they are made of metal. A rock, rubber band, and wooden stick are insulators because they cannot conduct electricity.
Answer:
21 m
Explanation:
The motion of the frog is a uniform motion (constant speed), therefore we can find the distance travelled by using

where
d is the distance covered
v is the speed
t is the time
The frog in this problem has a speed of
v = 2.1 m/s
and therefore, after t = 10 s, the distance it covered is
