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liberstina [14]

3 years ago

14

What kind of light source is an IMAX movie screen

1 answer:

kirill115 [55]3 years ago

4 0

Answer:

laser light source

Explanation:

A laser light source provides substantially more brightness than a xenon bulb, and allows IMAX to power its largest screens with even sharper and more lifelike images.

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What is the mathematical relationship between current, resistance, and voltage?

vlada-n [284]

Answer:

q=IR

Explanation:

q is voltage

I is current

R is resistance

6 0

3 years ago

F = 2.0*10^20 N,

natka813 [3]

$F=\dfrac{Gm_1m_2}{r^2}$

With the given values of $F,G,m_1,r$ , we have

$2.0\times10^{20}\,\mathrm N=\dfrac{\left(6.67\times10^{-11}\,\frac{\mathrm{Nm}^2}{\mathrm{kg}^2}\right)\left(5.98\times10^{24}\,\mathrm{kg}\right)m_2}{\left(3.8\times10^8\,\mathrm m\right)^2}$

Try dealing with the powers of 10 first: On the right, we have

$\dfrac{10^{-11}\times10^{24}}{(10^8)^2}=\dfrac{10^{24-11}}{10^{16}}=10^{-3}$

Meanwhile, the other values on the right reduce to

$\dfrac{6.67\times5.98}{3.8^2}\approx2.76$

Then taking units into account, we end up with the equation

$2.0\times10^{20}\,\mathrm N=\left(2.76\times10^{-3}\,\dfrac{\mathrm N}{\mathrm{kg}}\right)m_2$

Now we solve for $m_2$ :

$m_2=\dfrac{2.0\times10^{20}\,\mathrm N}{2.76\times10^{-3}\,\frac{\mathrm N}{\mathrm{kg}}}\approx0.725\times10^{20-(-3)}\,\mathrm{kg}$

$m_2=7.25\times10^{22}\,\mathrm{kg}$

or, if taking significant digits into account,

$m_2=7.3\times10^{22}\,\mathrm{kg}$

5 0

3 years ago

During the execution of a play, a football player carries the ball for a distance of 33 m in the direction 58° north of east. To

podryga [215]

Answer:28 m

Explanation:

Given

Direction is $58^{\circ}$ North of east i.e. $58 ^{\circ}$ with x axis

Also ball moved by 33 m

therefore its east component is 33cos58=17.48 m

Northward component $=33sin58=27.98 m\approx 28 m$

8 0

3 years ago

A man works on a striaght road from his home to market 2.5km away dwith a speed of 5km/h.Finding the market closed, he instantly

umka21 [38]

Answer:

5.625km/h

Explanation:

We are given that

Distance between home and market, d=2.5 km

Speed, v1=5km/h

Speed, v2=7.5 km/h

We have to find the average speed of the man over the interval of time 0 to 40min.

Time, $t=\frac{distance}{speed}$

Using the formula

$t_1=\frac{2.5}{5}=0.5 h=0.5\times 60=30 min$

1 hour =60 min

$t_2=\frac{2.5}{7.5}=\frac{1}{3}hour=\frac{60}{3}=20min$

Distance traveled by man in 10 min with speed 7.5 km/h= $\frac{2.5}{20}\times 10=2.5/2km$

Therefore,

Total distance covered=2.5+2.5/2=3.75 km

Time=40 min=40/60=2/3 hour

Average speed= $\frac{total\;distance}{total\;time}$

Average speed= $\frac{3.75}{2/3}=5.625km/h$

7 0

3 years ago

PLEASE HELP! The tendency of an object to resist any change in its motion is called

soldi70 [24.7K]

inertia is the answer!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

4 0

3 years ago

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