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jek_recluse [69]
3 years ago
12

A fisherman has caught a very large, 5.0kg fish from a dock that is 2.0m above the water. He is using lightweightfishing line th

at willbreak under a tension of 54N or more. He is eager to the fish to the dock in the shortest time possible. If the fish is at rest at the water's surface, what is the least amount of time in which the fisherman can raise the fish to the dock without losing it?
Physics
1 answer:
agasfer [191]3 years ago
7 0

Answer:

t = 2 s

Explanation:

As we know that fish is pulled upwards with uniform maximum acceleration

then we will have

T - mg = ma

here we know that maximum possible acceleration of so that string will not break is given as

T = 54 N

now we have

54 - (5 \times 9.8) = 5 a

a = 1 m/s^2

now for such acceleration we can use kinematics

d = \frac{1}{2}at^2

2 = \frac{1}{2}(1) t^2

t = 2 s

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Answer:

Change in momentum is zero.

Explanation:

The following data were obtained from the question:

Mass (m) = 5000 kg

Time (t) = 1 h

Net force (F) = 0

Change in momentum =?

Force = Rate of change of momentum

0 = change in momentum

Change in momentum = 0

We can see from the above illustration that the net force is zero. Thus, the change in momentum is also zero.

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In many cartoon shows, a character runs of a cliff, realizes his predicament and lets out a scream. He continues to scream as he
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7 0
3 years ago
Jennifer and Jamie have a class assignment to identify an example of climate change and an example of a change in weather. They
viva [34]

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8 0
3 years ago
The moon Umbriel orbits Uranus (mass = 8.68 x 10^25 kg) at a distance of 2.66 x 10^8 m. What is Umbriel's orbital period (in hou
Whitepunk [10]

Answer:

T = 99.51 hour

Explanation:

Mass of Uranus, M=8.68\times 10^{25}\ kg

The moon Umbriel orbits Uranus at a distance of 2.66\times 10^8\ m

We need to find Umbriel's orbital period. Let it is T. Using Kepler's third law of motion to find it.

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3 years ago
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